Answer
Gravity is what holds us down on the earth's (or moon's) surface. If you were to weigh yourself on a scale on Earth and then on the moon, the weight read on the moon would be 1/6 your earth weight
Explanation:
Given that,
Weight of water = 25 kg
Temperature = 23°C
Weight of mass = 32 kg
Distance = 5 m
(a). We need to calculate the amount of work done on the water
Using formula of work done



The amount of work done on the water is 1568 J.
(b). We need to calculate the internal-energy change of the water
Using formula of internal energy
The change in internal energy of the water equal to the amount of the work done on the water.


The change in internal energy is 1568 J.
(c). We need to calculate the final temperature of the water
Using formula of the change internal energy





The final temperature of the water is 23.01°C.
(d). The amount of heat removed from the water to return it to it initial temperature is the change in internal energy.
The amount of heat is 1568 J.
Hence, This is the required solution.
Answer:
Explained
Explanation:
A student who runs every day is becoming bored with her physical fitness routine and considers quitting. Now in order maintain her fitness routine she needs to break the monotony by changing her exercise regime. She do other activities like play sports two days a week, she do aerobics, she even try some cardio vascular exercises which as good as running. She also try changing her route of running as the new view might inspire her.
Your correct answer would be 0 N
The forces are pulling in opposite directions, therefore they cancel each other out.
Hope that helps!!
:)
Answer:
the distance between interference fringes increases
Explanation:
For double-slit interference, the distance of the m-order maximum from the centre of the distant screen is

where
is the wavelength, D is the distance of the screen, and d the distance between the slits. The distance between two consecutive fringes (m and m+1) will be therefore

and we see that it inversely proportional to the distance between the slits, d. Therefore, when the separation between the slits decreases, the distance between the interference fringes increases.