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murzikaleks [220]
3 years ago
9

How much tension is in a rope if it pulls a 5-kg bucket filled with water with an upward acceleration of 1m/s^2

Physics
1 answer:
liraira [26]3 years ago
4 0
F=ma
Tension - weight = mass x acceleration
T - 5(9.81) = 5 x 1
T = 5 + 5(9.81)
T = 54.05 N
T ≈ 54 N
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a_sh-v [17]

Answer:

3Q / 4 pi (R^3 - r^3)

Explanation:

Charge density = charge / volume

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4 years ago
Determine the position in the oscillation where an object in simple harmonic motion: (Be very specific, and give some reasoning
vladimir1956 [14]

Answer:

Explanation:

The greatest speed is attained at middle point or equilibrium point or where displacement from equilibrium point is zero .

When the object remains at one of the extreme point it experiences greatest acceleration but at that point velocity is zero . Due to acceleration , its velocity goes on increasing till it come to equilibrium point . At this point acceleration becomes zero . After that its velocity starts decreasing because of negative acceleration . Hence at middle point velocity is maximum .

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3 years ago
Two cars, one of mass 1300 kg, and the second of mass 2400 kg, are moving at right angles to each other when they collide and st
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To solve this problem we will apply the momentum conservation theorem, that is, the initial momentum of the bodies must be the same final momentum of the bodies. The value that will be obtained will be a vector value of the final speed of which the magnitude will be found later. Our values are given as,

m_1 = 1300kg

m_2 = 2400kg

u_1 = 12m/s i

u_2 = 18m/s j

Using conservation of momentum,

m_1u_1+m_2u_2 = (m_1+m_2)v_f

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Solving for v_f

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Using the properties of vectors to find the magnitude we have,

|v| = \sqrt{(4.2162^2)+(-11.6756)^2}

|v| = 12.4135m/s

Therefore the magnitude of the velocity of the wreckage of the two cars immediately after the collision is 12.4135m/s

6 0
3 years ago
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