<span>In this case we can see from the given that the
Sodium (Na) becomes a positive ion. When an atom becomes positive, therefore it
means that it lose an electron. Therefore sodium loses one electron and becomes
an ion with a positive charge (cation). This is written as: Na-----> Na+ + e</span>
Answer:
The veins (blue) take oxygen-poor blood back to the heart. Arteries begin with the aorta, the large artery leaving the heart. They carry oxygen-rich blood away from the heart to all of the body's tissues.
Explanation:
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In order to calculate the enthalpy of the reaction, we first calculate the heat released using the given formula.
Q = mc<span>ΔT
Q = 1000 x 4.184 x (35.65 - 24.85)
Q = 45187.2 J = 45.2 kJ
Now, we determine the moles of methane that were burned.
Moles = mass / Mr
Moles = 1.11 / (12 + 4)
Moles = 0.07
The enthalpy of a reaction is the energy released per mole, so the enthalpy in this case is:
</span>ΔH = 45.2 / 0.07
ΔH = 645.7 kJ/mol
Molarity is a way of expressing concentration that is equal to the ratio of the moles of the solute to the liters of solution. The amount of substance in moles can be calculated through,
moles = (molarity) x (volume in liters)
Substituting the values,
moles = (0.135 M) x (5.0 L) = 0.675 moles
Multiply this value with the molar mass of sodium ion,
mass = (0.675 moles) x (23 g/ mole) = 15.525 grams
Therefore, the mass of sodium ion in the blood is 15.525 grams.
Mass after 60 years:
2 kg of cesium-137 will remain after 60.0 years.
What is Half-life?
The duration needed for a quantity to decrease to half of its initial value is known as the half-life.
Given:
N0 = is the initial amount of cesium-137 = 8.0 Kg
N = is the amount remaining after a time = Unknown
t = Duration of cesium-137 decay in 8.0 Kg = 60 years
t1/2 = half-life of cesium-137 = 30.0 years
Formula = N/No = (1/2)^t/t1/2
After putting the value:
N/8= (1/2)^60/30
N/8= (1/2)^2
N/8= 1/4
4N= 8
N= 8/4
N= 2 Kg
As a result, 2 Kg of cesium-137 will be present after 60 years.
Learn more about the half-life here,
brainly.com/question/14018709
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