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8 months ago

if the central atom in a molecule is sp3 hybridized, how many different electronic geometries can it have?

Chemistry

1 answer:

jekas [21]8 months ago

6 0

Tetrahedral molecular geometry is the only one that can exist for sp3 hybridized center atoms.

<h3>Which chemical contains an sp3 hybridized central atom?</h3>

An atom that is bound and a nonponding pair of electrons are the two different kinds of electron domains.All bonded atoms count as one electron domain on the center atom, regardless of whether they are connected by a single, double, or triple bond.

There are five fundamental geometries for electron domains. The core oxygen atom in the water molecule has six valence electrons.The 6 valence electrons of oxygen are arranged in hybridized sp3 orbitals, resulting in 2 paired and 2 free electrons.

One s orbital and three p orbitals combine to generate four sp3 orbitals, each of which has a 25% s character and a 75% p character. This process is known as sp3 hybridization.

An example of CO2 can be used to illustrate how lone pairs of electrons make up an SP3 hybrid orbital.We are only able to count bond pairs or lone bonds.

To learn more about sp3 refer

brainly.com/question/28359475

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if 45.0 ml of 1.50 M Ca(OH)2 are needed to neutralize 25.0 ml of HI of unknown concentration, what is the molarity of the HI?

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Answer:

M of HI = 5.4 M.

Explanation:

We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.

(XMV) acid = (XMV) base.

where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.

M is the molarity of the acid or base.

V is the volume of the acid or base.

(XMV) HI = (XMV) Ca(OH)₂.

For HI; X = 1, M = ??? M, V = 25.0 mL.

For Ca(OH)₂, X = 2, M = 1.5 M, V = 45.0 mL.

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3 years ago

It takes 49.0J to raise the temperature of an 11.5g piece of unknown metal from 13.0?C to 24.3?C. What is the specific heat for

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Answer:

c = 0.377 J/g.°C

c = 0.2350 J/g.°C

J = 27.3 J

Explanation:

We can calculate the heat (Q) absorbed or released by a substance using the following expression.

Q = c × m × ΔT

where,

c: specific heat

m: mass

ΔT: change in the temperature

It takes 49.0J to raise the temperature of an 11.5g piece of unknown metal from 13.0°C to 24.3°C. What is the specific heat for the metal? Express your answer numerically, in J/g.°C

Q = c × m × ΔT

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c = 0.377 J/g.°C

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