Answer:
Explanation:
Given
Pipe is lowered to the water
Negative Pressure is applied to raise the water
Pressure is given by
where
(b)8.82 atm is much lower than the vapor pressure of water
(c)The fact of applying a negative pressure of 8.74 below the vapor pressure of water
Answer: C) The two particles will move away from each other
Explanation:
When two electrically charged bodies come closer, appears a force that attracts or repels them, depending on the sign of the charges of this two bodies.
This is stated by Coulomb's Law:
"The electrostatic force between two point charges
and
is proportional to the product of the charges and inversely proportional to the square of the distance
that separates them, and has the direction of the line that joins them"
Mathematically this law is written as:
Where is a proportionality constant.
Now, if and
have the same sign charge (both positive or both negative), a repulsive force will act on these charges.
Answer:
the force of attraction between the two charges is 3.55 N.
Explanation:
Given;
first charge carried by the object, q₁ = 15.5 µC
second charge carried by the q₂ = -7.25 µC
distance between the two charges, r = 0.525 m
The force of attraction between the two charges is calculated as;
Therefore, the force of attraction between the two charges is 3.55 N.