11. a 0.12-kg, 50-cm-long uniform bar has a small 0.055-kg mass glued to its left end and a small 0.11-kg mass glued to the othe
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Answer:
1184 kJ/kg
Explanation:
Given:
water pressure P= 28 bar
internal energy U= 988 kJ/kg
specific volume of water v= 0.121×10^-2 m^3/kg
Now from steam table at 28 bar pressure we can write
therefore at saturated liquid we have specific enthalpy at 55 bar pressure.
that the specific enthalpy h = h at 50 bar +(55-50)/(60-50)*( h at 50 bar - h at 60 bar)
h= 1184 kJ/kg