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lawyer [7]
1 year ago
12

The wavelength of the yellow light from a sodium flame is 589 nm. This light originated from a sodium atom in the hot flame.

Physics
1 answer:
DiKsa [7]1 year ago
6 0

From wave speed formula, period is 1.96 × 10^-15  seconds per cycle and the frequency is 5.1 × 10^14 Hertz

<h3>What is Frequency ?</h3>

The frequency of a wave is the number of complete revolution per second made by a vibrating body.

Given that the wavelength of the yellow light from a sodium flame is 589 nm. This light originated from a sodium atom in the hot flame.

(a) In the sodium atom from which this light originated, the period of the simple harmonic motion which was the source of this electromagnetic wave will be found by using the formula

v = λ/T

Where

  • v = speed of light = 300,000,000 m/s
  • λ = wavelength = 589 × 10^-9 m
  • T = period

Substitute all the parameters

300000000 = 589 × 10^-9/T

T = 589 × 10^-9/300000000

T = 1.96 × 10^-15  seconds per cycle.

(b) The frequency of this light wave is the reciprocal of its period. That is,

F = 1/T

F = 1/1.96 × 10^-15

F = 5.1 × 10^14 Hertz

Therefore, the period of the wave is 1.96 × 10^-15  seconds per cycle and its frequency is 5.1 × 10^14 Hertz

Learn more about Light Wave here: brainly.com/question/10728818

#SPJ1

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Answer:

12.56 A.

Explanation:

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H = I/2πr ............................... Equation 1

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Making I the subject of the equation,

I = 2πrH............... Equation 2

Given: H = 1 T, r = 2 m.

Constant: π = 3.14

Substitute into equation 2

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I = 12.56 A.

Hence, the magnetic field = 12.56 A.

5 0
3 years ago
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Answer:

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Explanation:

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7 0
3 years ago
This problem has been solved!
lana66690 [7]

Answer:

Charge on each metal sphere will be 8\times 10^{8}C

Explanation:

We have given number of electron added to metal sphere A n=10^{12}electron

As both the spheres are connected by rod so half -half electron will be distributed on both the spheres.

So electron on both the spheres =\frac{10^{12}}{2}=5\times 10^{11}electron

We know that charge on each electron e=1.6\times 10^{-19}C

So charge on both the spheres will be equal to q=1.6\times 10^{-19}\times 5\times 10^{11}=8\times 10^{8}C

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2 years ago
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2 years ago
Two planets have the same surface gravity, but planet b has twice the radius of planet
vampirchik [111]
Planet A;
m = the mass 
Let r =  the radius 

Planet B:
Let M =  the mass
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Answer: The mass of planet B is 4m.
3 0
3 years ago
Read 2 more answers
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