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mixas84 [53]
4 years ago
6

Which of the following describes what needs to occur in order to reduce force while doing the same amount of work?

Physics
1 answer:
VikaD [51]4 years ago
5 0
Among the choices the choices the one that describes what needs to occur in order to reduce force while doing the same amount of work is <span> the distance over which the force is exerted must decrease. The answer is B. 

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
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The space shuttle approaches earth at a speed of 2.89*10^4 km/h when it sends a radio signal to earth 1.00*10^5 km away. The rad
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Answer:

3 secods later

Explanation:

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I can fly but have no wings. I can cry but I have no eyes. Wherever I go, darkness follows me. What am I?
nlexa [21]

cloud?? thats prob wrong lol

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3 years ago
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A group of students are provided with three objects all of the same mass and radius. The objects include a solid cylinder, a thi
SOVA2 [1]

Answer:

Sphere, cylinder    hoop

Explanation:

To analyze Which student is right it is best to propose the solution of the problem. Let's look for the speed of the center of mass. Let's use the concept of mechanical energy

In the highest part of the ramp

     Em₀ = U = mg y

In the lowest part

Here the energy has part of translation and part of rotation

      E_{mf}  = K_{T} + K_{R}

      E_{mf}  = ½ m v_{cm}² + ½ I w²

Where I is the moment of inertia of the body and w the angular velocity that relates to the velocity of the center of mass

     v_{cm} = w r

    w = v_{cm} / r

Let's replace

   E_{mf} = ½ I (v_{cm} / r)²

Energy is conserved

   mg y = ½ m v_{cm}² + ½ I v_{cm}² / r2

   ½ (m + I / r²) v_{cm}² = m g y

   ½ (1 + I / m r²) v_{cm}² = g y

   v_{cm} = √ [2gy / (1 + I / mr²)]

This is the velocity of the center of mass of the bodies, as they all have the same radius with comparing this point is sufficient. Now let's use the speed definition

   v = d / t

   t = d / v

   t = d / (√ [2gy / (1 + I / mr²)])

   t = (d / √ 2gy) √(1 + I / m r²)

Therefore we see that time is proportional to the square root. All quantities are constant and the one that varies is the moment of inertia.

The moments of inertia of

Sphere is   Is = 2/5 M r²

Cylinder    Ic = ½ M r²

Hoop         Ih = M r²

Let's replace each one and calculate the time

Sphere

    ts = (d / √2gy) √ (1 + 2/5 Mr² / mr²)

    ts = (d / √ 2gy) √ (1 +2/5) = (d / √ 2gy) √(1.4)

    ts = (d / √ 2gy)      1.1

Cylinder

    tc = (d / √2gy) √ (1 + 1/2 Mr² / Mr²)

    tc = (d / √2gy) √ (1 + ½) = (d / √ 2gy) √ 1.5

    tc = (d / √ 2gy)    1.2

Hoop

    th = (d / √2gy) √ (1 + mr² / mr²)

    th = (d / √2gy) √(1 + 1) = (d / √ 2gy) √ 2

    th = (d / √ 2gy)  1.41

We have the results for the time the body that arrives the fastest is the sphere and the one that is the most hoop. Therefore the correct answer is

         ts < tc < th

     Sphere, cylinder    hoop

5 0
3 years ago
Type of bacteria that attacks the throat- causing fever sore throat rash
Law Incorporation [45]

Answer:

Streptococcus Pyogenes

Explanation:

Strep throat!

4 0
3 years ago
What is the entropy change of a 0.349 g spoonful of water that evaporates completely on a hot plate whose temperature is slightl
quester [9]

Answer:

\Delta S = 2.11 J/K

Explanation:

As we know that entropy change for phase conversion is given as

\Delta S = \frac{\Delta Q}{T}

Here we know that heat required to change the phase of the water is given as

\Delta Q = mL

here we have

m = 0.349 g = 3.49\times 10^{-4} kg

L = 2250000 J/kg

now we have

\Delta Q = (3.49 \times 10^{-4})\times 2250000

\Delta Q = 788.9 J

also we know that temperature is approximately same as boiling temperature

so we have

T = 373 k

so here we have

\Delta S = \frac{788.9}{373}

\Delta S = 2.11 J/K

3 0
3 years ago
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