an 75-kilogram skier slides on waxed skis along a horizontal surface of snow at constant velocity while pushing with his poles.
1 answer:
You might be interested in
By Considering the vertical distance and both vertical and horizontal final velocity, the time t = 0.45 s and Velocity V = 6.7 m/s
Given that a Veggie meatball with v = 5.0 m/s rolls off a 1.0 m high table.
Height h = 1.0 m
As the ball rolls off the table, it will be fallen under gravity. Where
g = 9.8 m/
Initial vertical velocity = 0
Initial horizontal velocity = 5 m/s
Considering the vertical distance, the formula to use to calculate the time will be;
h = ut + 1/2g
1 = 0 + 1/2 x 9.8
1 = 4.9
= 1/4.9
t =
t = 0.45 seconds
It takes 0.45 seconds to hit the floor if no one sneezes.
To calculate its velocity when it hits the floor, we will need to calculate for both vertical and horizontal final velocity and find the resultant velocity of the two.
Vertical component
=
+ gt
= 0 + 9.8(0.45)
= 4.41 m/s
Horizontal component
=
+ at
but a = 0
= 5 m/s
Final velocity V =
V = 6.67 m/s
Therefore, it will hit the floor at a velocity of 6.7 m/s
Learn more here: brainly.com/question/5063616
Answer:
i) No, the spring scale does not read a different value
ii) The torque will read a different value, it will reduce
iii) The spring scale does not need to be measured at the center of mass location.
Explanation:
The torque caused by the gyroscope can be given by the relation,
r × f
The torque measured by the gyroscope varies directly with the distance, r.
A decrease in the distance r will also cause a decrease in the value of the torque measured. When the distance, r is reduced from 7.5 inches to 5 inches, the torque caused by the gyroscope's weight also reduces.
The weight of the gyroscope remains constant despite the reduction in the distance because the weight of the gyroscope is not a function of the distance from the gyroscope. Therefore, the spring scale will not read a different value.
Yes, the spring scale does not need to be measured from the center of mass location because the weight does not depend on the location of measurement. The reading of the sprig scale remains constant.