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Readme [11.4K]
1 year ago
8

Why does a homogenous linear system in n unknowns whose corresponding augmented matrix with rref containg n leading 1s, then the

linear system onlyhas the trivial solution?
Chemistry
1 answer:
Flauer [41]1 year ago
3 0

A homogeneous system always has a nontrivial solution if the number of equations is less than the number of unknowns.

<h3><u>What is </u><u>homogenous linear system </u><u>?</u></h3>

A homogeneous system of linear equations where each equation's constant term is equal to 0. Therefore, there are no constant terms in any equation for such systems. There might be one solution or infinitely many for a homogeneous linear system. But there is always at least one answer.

There are no constant terms in a homogeneous system of linear equations, which is a linear equation system.

There are two different kinds of solutions for a homogeneous system: trivial solutions and nontrivial solutions. Since there is no constant term in homogeneous systems, the simple solution is (x₁, x₂, ..., xₙ) = (0, 0,..., 0), which is an evident solution to the problem (the most obvious solution). For instance, the solution (x, y, z) = is simple for the system created by the three equations x + y + z = 0, y - z = 0, and x + 2y = 0. (0, 0, 0).

To view more about homogenous linear system, refer to:

brainly.com/question/13391708

#SPJ4

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. How many moles are there in 8.5x 1025 molecules of co2
bogdanovich [222]
1 mole => 6.023 x 10^23 molecules

x => 8.5 x 10^25 molecules

x = 8.5x10^25/ 6.023 x 10^23 = 141.1 



6 0
3 years ago
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A 0.1014 g sample of a purified compound containing C, H, and, O was burned in a combustion apparatus and produced 0.1486 g CO2
Alina [70]

Answer: The empirical formula for the given compound is CH_2O

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=0.1486g

Mass of H_2O=0.0609g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.1486 g of carbon dioxide, \frac{12}{44}\times 0.1486=0.0405g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.0609 g of water, \frac{2}{18}\times 0.0609=0.00677 of hydrogen will be contained.

Mass of oxygen in the compound = (0.1014) - (0.0405 + 0.00677) = 0.054 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.0405g}{12g/mole}=0.003375moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.00677g}{1g/mole}=0.00677moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.054g}{16g/mole}=0.003375moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.485 moles.

For Carbon = \frac{0.003375}{0.003375}=1

For Hydrogen  = \frac{0.00677}{0.003375}=2.00\times 2

For Oxygen  = \frac{0.003375}{0.003375}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 2 : 1

The empirical formula for the given compound is C_1H_2O_1=CH_2O

Thus, the empirical formula for the given compound is CH_2O

8 0
3 years ago
A 1.2 L weather balloon on the
makkiz [27]

Answer:

330.95K

Explanation:

V₁ = 1.2L

T₁ = 25°C = (25 + 273.15)K = 298.15K

P₁ = 1.0 atm

P₂ = 0.74 atm

V₂ = 1.8L

T₂ =?

From combined gas equation,

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

Solve for T₂

T₂ = (P₂ * V₂ * T₁) / (P₁ * V₁)

T₂ = (0.74 * 1.8 * 298.15) / (1.0 * 1.2)

T₂ = 397.1358 / 1.2

T₂ = 330.9465K

T₂ = 330.95K or T₂ = (330.95 - 273.15)°C = 57.8°C

8 0
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An analogy is a comparison between two things
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A metaphor is a figure of speech where a word or phrase is applied and it’s not literal.
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What layer of the atmosphere is the ozone layer in?
vodomira [7]

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