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Sergeeva-Olga [200]
2 years ago
15

A 2.0-kilogram ball rolls down a ramp. if the ball accelerates at a rate of 12 m/s2, the net force causing the acceleration is:

Physics
1 answer:
ehidna [41]2 years ago
7 0

Answer:

D

Explanation:

f = ma

2 x 12 = 24

answer could differ since it's rolling down a ramp. if an angle is given our approach differs.

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Which of the following will be attracted toward a positively charged cloth?
Elden [556K]

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sound waves and light energy are not "affected" by static electricity

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2 years ago
What is the vertical acceleration of a paper airplane that is launched horizontally with an initial velocity of 2.3 m/s?
mr_godi [17]

Answer:

<em>The vertical acceleration is -9.81 m/s^2</em>

Explanation:

When a body is projected, the body experiences an acceleration in the vertical axis that is proportional to the acceleration due to gravity of the earth, which is equal to 9.81 m/s^2. In this case, the acceleration acts to stop the vertical motion of the paper plane, and hence is a deceleration, which explains the negative vertical acceleration.

8 0
3 years ago
1. Describe your egg drop apparatus and at least three (3) design features you implemented in order to try to help your egg surv
Olegator [25]

Answer:

Explanation:

There are three basic ways to increase the likelihood of safely dropping an egg:

Slow down the descent speed.

Parachutes are an obvious method for slowing the decent speed, as long as the design includes a way to keep the parachute open.

Cushion the egg so that something other than the egg itself absorbs the impact of landing.

The largest end of the egg has an area of air trapped between the egg's two membranes. This air space forms when the contents of the egg cool and contract after the egg is laid. It accounts for the crater you often see at the end of a hard-cooked egg. Upon impact the heavier spherical yolk continues moving towards the ground. The compression of the airspace acts like an air bag for the eggs' valuable contents. Building an artificial cushioning device will also help absorb the impact of landing.

The largest end of the egg has an area of air trapped between the egg's two membranes. This air space forms when the contents of the egg cool and contract after the egg is laid. It accounts for the crater you often see at the end of a hard-cooked egg. Upon impact the heavier spherical yolk continues moving towards the ground. The compression of the airspace acts like an air bag for the eggs' valuable contents. Building an artificial cushioning device will also help absorb the impact of landing.

Orient the egg so that it lands on the strongest part of the shell.

The arch structure at either end of the egg is stronger than its sides. Pressure is distributed down (or up) the arches so that less pressure acts on any one point. Orienting the arch downwards will increase the egg's survival.

Hope this helps you

5 0
2 years ago
To what tension (in newtons) must you adjust the screw so that a transverse wave of wavelength 3.33 cm makes 621 vibrations per
PilotLPTM [1.2K]

Answer:

T=9.4 N

Explanation:

We are given that

Mass of wire,m=16.5 g=\frac{16.5}{1000}kg

1 kg=1000g

Length of wire,l=75 cm=75\times 10^{-2}m

1 m=100 cm

Wavelength of transverse wave=\lambda=3.33 cm=3.33\times 10^{-2}m

Frequency=621 Hz

Mass per unit length=m_l=\frac{m}{l}=\frac{16.5}{1000\times 75\times 10^{-2}}=0.022 kg/m

\nu=\frac{v}{\lambda}

v=\nu \lambda

Where\nu=frequency of wave

\lambda=Wavelength of wave

Speed of wave=v

Using the formula

v=3.33\times 10^{-2}\times 621=20.7m/s

v=\sqrt{\frac{T}{m_l}}

v^2=\frac{T}{m_l}

T=v^2m_l

Using the formula

T=(20.7)^2\times 0.022=9.4N

Hence, the tension,T=9.4 N

7 0
3 years ago
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