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expeople1 [14]
3 years ago
6

Swim 2km at 3km/h. Run at 12km/h for 1 ½ hours. Cycling 55km at 30 km/h. What is the mean overall speed.

Physics
1 answer:
exis [7]3 years ago
5 0

Answer:

t1 = S1 / V1 = 2 km / 3 km/hr = 2/3 hr        where S1 = 2 km

S2 = 12 km/hr * 3/2  hr = 18 km      where t2 = 3/2 hr

t3 = S3 / V3 = 55 km / 30 km/hr = 11/6 hr   where S3 = 55 km

T = t1 + t2 + t3 = 4/6 + 9/6 + 11 / 6 = 24/6 = 4 hrs

S = S1 + S2 + S3 = 2 + 18 + 55 = 75 km

V =  S / T = 75 km / 4 hrs = 18.75 km/hr     for the average speed

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boyakko [2]

The fatal current is 51 mA = 0.051 Ampere.

The resistance is 2,050Ω .

Voltage = (current) x (resistance)

            =  (0.051 Ampere) x (2,050 Ω)  =  104.6 volts .

==================

This is what the arithmetic says IF the information in the question
is correct.

I don't know how true this is, and I certainly don't plan to test it,
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heart can be fatal, not  51 mA .

If 15 mA can do it, and the sweaty electrician's resistance is
really 2,050 Ω, then the fatal voltage could be as little as  31 volts !

The voltage at the wall-outlets in your house is  120 volts in the USA !
THAT's why you don't want to stick paper clips or a screwdriver into
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6 0
3 years ago
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3 years ago
Please choose the answer that describes the scientific notation for 3,134,000,000.
Ghella [55]
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7 0
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Two movers are pushing a large crate with a force of 60.0 n each. one pushes north, the other east. what is the equilibrant forc
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To get the solution you must need to draw a force triangle. Attach the head of the 60N north force arrow with the tail of the 60N east force arrow. The subsequent is the arrow connecting he tail and head of the two arrows. 
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8 0
3 years ago
A container of gas is at a pressure of 3.7 x 10^5 Pa. How much work is done by the gas if its volume expands by 1.6 m^3 ?
Dmitriy789 [7]

Answer:

592000 J

Explanation:

We'll begin by converting 3.7×10⁵ Pa to Kg/ms². This can be obtained as follow:

1 Pa = 1 Kg/ms²

Therefore,

3.7×10⁵ Pa = 3.7×10⁵ Kg/ms²

Next, we shall determine the workdone.

Workdone is given by the following equation:

Workdone (Wd) = pressure (P) × change in volume (ΔV)

Wd = PΔV

With the above formula, the work done can be obtained as follow:

Pressure (P) = 3.7×10⁵ Kg/ms²

Change in volume (ΔV) = 1.6 m³

Workdone (Wd) =?

Wd = PΔV

Wd = 3.7×10⁵ × 1.6

Wd = 592000 Kgm²/s²

Finally, we shall convert 592000 Kgm²/s² to Joule (J). This can be obtained as follow:

1 Kgm²/s² = 1 J

Therefore,

592000 Kgm²/s² = 592000 J

Therefore, the Workdone is 592000 J.

6 0
3 years ago
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