Which is formed by positive ions from a base and negative ions from an acid? a. Salt b. Vinegar

Chemistry

1 answer:

max2010maxim [7]10 months ago

3 0

The formation of salt takes place by the sharing of positive ions from a base and negative ions from an acid.

This is based on the concept and principles of neutralization. The process of neutralization is the name of a chemical reaction between an acid and a base.

Hence, the correct option is a.

pH refers to a measure of how acidic or basic a solution is.

A pH is a measure of how basic or acidic a substance is. pH has a range of 0-14. A pH greater than 7 means the substance is basic.

A pH less than 7 means the substance is acidic. When the pH is exactly 7 that indicates that the substance is neutral.

Hence, the correct optiion is a.

The pH of a solution that has the same number of hydrogen ions as hydroxide ions is 7.

Hence, the correct option is c.

Baking soda has the greatest number of hydroxide ions.

Thus is because of the pH is 9. So, it will be more basic.

Hence, the correct option is a.

Hydrochloric acid will be least likely to completely dissolve in water.

Hence, the correct option is a.

Antacid is taken to get relieve from heartburn describes that the antacid is acidic and will raise the pH of the esophagus.

Hence, the correct option is c.

Acids measure below 7 describes the pH scale.

Hence, the correct option is a.

The order of these solutions from strong acid to strong base is

Ammonia>battery acid>stomach acid>antacid>baking soda.

To know more about pH here

brainly.com/question/3775914

#SPJ4

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ILL GIVE U BRAINILIEST

Arte-miy333 [17]

1:3 hope DAT helps #ZedTheZom

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3 years ago

If acetic acid is the only acid that vinegar contains (ka=1.8×10−5), calculate the concentration of acetic acid in the vinegar.

kicyunya [14]

Ethanoic (Acetic) acid is a weak acid and do not dissociate fully. Therefore its equilibrium state has to be considered here.

$CH_{3}COOH \ \textless \ ---\ \textgreater \ H^{+} + CH_{3}COO^{-}$

In this case pH value of the solution is necessary to calculate the concentration but it's not given here so pH = 2.88 (looked it up)

pH = 2.88 ==> $[H^{+}]$ = $10^{-2.88}$ = 0.001 $moldm^{-3}$

The change in Concentration Δ $[CH_{3}COOH]$ = 0.001 $moldm^{-3}$

  CH3COOH H+ CH3COOH
Initial   $moldm^{-3}$      $x$ 0 0

Change $moldm^{-3}$ -0.001 +0.001 +0.001

Equilibrium $moldm^{-3}$ $x$ - 0.001 0.001 0.001


Since the $k_{a}$ value is so small, the assumption
$[CH_{3}COOH]_{initial} = [CH_{3}COOH]_{equilibrium}$ can be made.

$k_{a} = [tex]= 1.8*10^{-5} = \frac{[H^{+}][CH_{3}COO^{-}]}{[CH_{3}COOH]} = \frac{0.001^{2}}{x}$

Solve for x to get the required concentration.

note: 1.)Since you need the answer in 2SF don&t round up values in the middle of the calculation like I've done here.

2.) The ICE (Initial, Change, Equilibrium) table may come in handy if you are new to problems of this kind

Hope this helps!

8 0

3 years ago

A compound was found to be soluble in water. It was also found that addition of acid to an aqueous solution of this compound res

gogolik [260]

Answer:

c. Cr

Explanation:

$Cr^3+(aq) + CO_3^2-(aq) ------------> Cr_2CO_3(s)$