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FrozenT [24]
2 years ago
10

A large meteoroid enters the Earth's atmosphere at a speed of 20.0 km/s and is not significantly slowed before entering the ocea

n. (a) What is the Mach angle of the shock wave from the meteoroid in the lower atmosphere?
Physics
1 answer:
Shalnov [3]2 years ago
5 0

The shock wave from the meteoroid in the lower atmosphere has a Mach angle of 0.948°.

(a) The meteoroid's speed v_s=20 \mathrm{~km} / \mathrm{s}

$=20 \times 10^3 \mathrm{~m} / \mathrm{s}$

Air sound wave speed &v=331 \mathrm{~m} / \mathrm{s} \\

Speed of the shock wave in Mach &\qquad \theta=\sin ^{-1}\left(\frac{v}{v_s}\right)

                                                            $$\begin{aligned}&=\sin ^{-1}\left(\frac{331 \mathrm{~m} / \mathrm{s}}{20 \times 10^3 \mathrm{~m} / \mathrm{s}}\right) \\&=0.948^{\circ}\end{aligned}$$

Hence, 0.948° is the Mach angle of the shock wave from the meteoroid in the lower atmosphere.

<h3>What is the speed of the meteoroid?</h3>

A meteoroid's speed can be loosely broken down into three categories: slow, medium, and fast.

  • Slow meteors move around the sun at a leisurely pace of about 32 kilometers per second (20 miles per second).
  • Medium-speed meteors travel around the sun at approximately 50 kilometers per second (30 miles per second),
  • while fast meteors zoom past at over 120 kilometers per second (75 miles per second)!

To learn more about meteoroid, visit:

brainly.com/question/1939309

#SPJ4

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A box of mass 60 kg is at rest on a horizontal floor that has a static coefficient of friction of 0.6 and a kinetic coefficient
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Answer:

a) The minimum force required to start moving the box is 352.86 N

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ii) The acceleration of box is 4.21625 m/s²

Explanation:

The parameters of the box at rest and the floor are;

The mass of the box = 60 kg

The static coefficient friction of the floor = 0.6

The kinetic coefficient friction of the floor = 0.25

Frictional force = Normal force × Friction coefficient

For an horizontal floor and the box laying on the floor, we have;

The normal force = The weight of the box = Mass of the box × Acceleration due to gravity, g

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The weight of the box  = 60 × 9.81 = 588.6 N

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Therefore;

The minimum force required to start moving the box = The static frictional force = Weight of the box × The static coefficient of friction

The minimum force required to start moving the box = 588.1 × 0.6 = 352.86 N

The minimum force required to start moving the box = 352.86 N

b) i) When an horizontal force of 400 N is applied, the applied force is larger than the static friction force, and the box will be in motion with the kinetic coefficient of friction being the source of friction

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a = 252.975 N/(60 kg) = 4.21625 m/s²

Acceleration of box, a = 4.21625 m/s².

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