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3 years ago

Does uranium use steam?

Physics

1 answer:

Neko [114]3 years ago

4 0

Answer:

Yes.

Explanation:

Reactors use uranium for nuclear fuel. The uranium is processed into small ceramic pellets and stacked together onto sealed metal tubes called fuel rods. The heat created by fission turns the water into steam.

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Your go-cart breaks down right before the end of a race, so you have to push it over the finish line. The go-cart has a mass of

Flura [38]

a) W=mg=833 N by definition

b) F=ma=76.5 N according to Newton's second law

c) a=F/m=4.12 m/s^2

d) m=F/a=720/5.5=130.91 kg

6 0

3 years ago

A car undergoing uniform acceleration travels 100 meters from a standing start in a given period of time. If the time were incre

iogann1982 [59]

Answer:

d = 1600 m

Explanation:

If car start from rest and accelerates uniformly then the displacement of the car is given as

$d = v_i t + \frac{1}{2}at^2$

now we know

$d = 0 + \frac{1}{2}at^2$

now if the same car will accelerate from rest for four times of the previous time interval

then we will have

$d = 0 + \frac{1}{2}a(4t)^2$

$d = 16(\frac{1}{2}at^2)$

so the distance will be 16 times more

$d = 1600 m$

5 0

4 years ago

A 5kg block rests on a 30° incline. The coefficient of static friction between the block and the incline is 0.20. How large a ho

Lelu [443]

Answer:

Hope It Help

Explanation:

That's all I know

6 0

3 years ago

Read 2 more answers

A gas undergoes two processes. In the first, the volume remains constant at 0.170 m3 and the pressure increases from 1.50×105 Pa

Mnenie [13.5K]

Answer:

$W_{T} = - 24 kJ$

Explanation:

The work (W) done by the gas can be calculated using the following equation:

$W = p*\Delta V = p*(V_{f} - V_{i})$

<u>Where:</u>

p: is the pressure

[tex}V_{f}[/tex]: is the final volume

[tex}V_{i}[/tex]: is the initial volume

In the first process, the work done by the gas is:

$W_{1} = p*\Delta V = p*0 = 0$

Since the volume remains constant, the total work done by the gas is equal to zero.

In the second process, the work done by the gas is:

$W_{2} = p*(V_{f} - V_{i}) = 6.00 \cdot 10^{5} Pa*(0.130 m^{3} - 0.170 m^{3}) = -24 kJ$

Now, the total work done by the gas during both processes is:

$W_{T} = W_{1} + W_{2} = 0 + (-24 kJ) = - 24 kJ$

Therefore, the total work done by the gas during both processes is - 24 kJ.

I hope it helps you!

7 0

4 years ago

Light with a single wavelength falls on two slits separated by 0.510 mm. In the resulting interference pattern on a screen 2.24

scZoUnD [109]

Answer: 655.7 nm

Explanation:

Given

The slits are separated by $d=0.510\ mm$

Distance between slits and screen is $D=2.24\ m$

Adjacent bright fringes are $\beta =2.88\ mm$ apart

Also, the distance between bright fringes is given by

$\Rightarrow \beta =\dfrac{\lambda D}{d}\quad [\lambda=\text{Wavelength of light}]\\\\\text{Insert the values}\\\\\Rightarrow 2.88\times 10^{-3}=\dfrac{\lambda \cdot 2.24}{0.510\times 10^{-3}}\\\\\Rightarrow \lambda =\dfrac{2.88\times 10^{-3}\times 0.510\times 10^{-3}}{2.24}\\\\\Rightarrow \lambda =0.6557\times 10^{-6}\ m\\\Rightarrow \lambda =655.7\ nm$

7 0

3 years ago