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bija089 [108]
3 years ago
10

In the author's opinion, why is attitude the most important fitness level factor to consider? (

Physics
1 answer:
Cerrena [4.2K]3 years ago
5 0
That's up to you because you have to go through the book to see their expressions
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the net external force on the 24-kg mower is stated to be 51 N. If the force of friction opposing the motion is 24 N, what force
-Dominant- [34]

Answer:

PART A)

External force will be 75 N

PART B)

distance moved will be 1.125 m

Explanation:

PART A)

Given that net force on the mower is

F_{net} = 51 N

now we also know that friction force due to ground is given as

F_f = 24 N

now we have

F_{net} = F_{ext} - F_f

51 = F_{ext} - 24

F_{ext} = 75 N

so external force will be 75 N

PART B)

deceleration due to friction when external force is removed from it

a = \frac{F_f}{m}

a = \frac{24}{24} = 1 m/s^2

now we can find the distance by kinematics

v_f^2 - v_i^2 = 2 a d

0 - 1.5^2 = 2(-1)d

d = 1.125 m

so the distance moved will be 1.125 m

6 0
3 years ago
a mass of 1.00 kg of water at temperature T is poured from a height of 0.100 km into a vessel containing water of the same tempe
Mariana [72]

Answer:

1.34352 kg

Explanation:

m_w = Mass of water falling = 1 kg

h = Height of fall = 0.1 km

\Delta T = Change in temperature = 0.1

c = Specific heat of water = 4186 J/kg K

g = Acceleration due to gravity = 9.81 m/s²

m_v = Mass of water in the vessel

Here the potential energy will balance the internal energy

m_wgh=m_wc\Delta T+m_vc\Delta T\\\Rightarrow m_v=\dfrac{m_wgh-m_wc\Delta T}{c\Delta T}\\\Rightarrow m_v=\dfrac{m_wgh}{c\Delta T}-m_w\\\Rightarrow m_v=\dfrac{1\times 9.81\times 100}{4186\times 0.1}-1\\\Rightarrow m_v=1.34352\ kg

Mass of the water in the vessel is 1.34352 kg

6 0
3 years ago
Differenciate between fundamentals quantities and derived quantities
REY [17]

Answer:

Fundamental quantities are the base quantities of a unit system, and they are defined independent of the other...

• Derived quantities are based on fundamental quantities, and they can be given in terms of fundamental quantities.

• In SI units, derived units are often given names of people such as Newton and Joule.

Explanation:

3 0
3 years ago
Read 2 more answers
I need help with the second one asap
dangina [55]

Answer:

what I don't know show a question mark me as brainleast

6 0
3 years ago
Read 2 more answers
F = Gm2/r2 G = ?<br> Fr2/m2<br> Fm2/r2<br> √(F)m/r<br> √(F)r/m
trapecia [35]

Answer: G=F\frac{r^{2}}{m^{2}}

Explanation:

We have the following equation:

F=G\frac{m^{2}}{r^{2}}

We have to find G this means we have to isolate it:

Fr^{2}=Gm^{2}

G=F\frac{r^{2}}{m^{2}}

8 0
3 years ago
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