**Answer:**

108.3g

**Explanation:**

**Given parameters: **

Volume of solution = 570mm = 0.57L (1000mm = 1L)

Molarity of solution = 2M

**Unknown**

Mass of MgCl₂

**Solution**

We first find the number of moles in the given concentration of magnessium chloride using the expression below:

Number of moles of MgCl₂= Molarity x volume = 2 x 0.57 = **1.14moles**

Using this known moles, we can the unknown mass of MgCl₂ the technician would require:

Mass of MgCl₂ required = number of moles of MgCl₂ x molar mass

Molar mass of MgCl₂:

Atomic mass of Cl = 35.5g

Atomic mass of Mg = 24g

MgCl₂ = 24 + (35.5x2) = 95gmol⁻¹

**Mass of MgCl₂ required = 1.14mole x 95gmole⁻¹ = 108.3g**