A 150kg motorcycle starts from rest and accelerates at a constant rate along a distance of 350m. The applied force is 250N and t
1 answer:
A) The net force on the motorbike is 205.9 N
B) The acceleration of the motorbike is
C) The final speed is 5.2 m/s
D) The elapsed time is 3.80 s
Explanation:
A)
There are two forces acting on the motorbike:
- The applied force, F = 250 N, forward
- The frictional force, , backward
The frictional force can be written as
where
is the coefficient of kinetic friction
is the mass of the motorbike
is the acceleration of gravity
Therefore the net force is given by
And substituting, we find
2)
The acceleration of the motorbike can be found by using Newton's second law, which states that the net force is equal to the product between mass and acceleration:
where
m is the mass
a is the acceleration
In this problem, we have
is the net force
m = 150 kg is the mass
Solving for a, we find the acceleration:
C)
Since the motion of the motorbike is a uniformly accelerated motion, we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For this motorbike, we have:
u = 0 (it starts from rest)
s = 350 m
Solving for v,
4)
For this part of the problem, we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the elapsed time
Here we have:
v = 5.2 m/s
u = 0
Solving for t, we find
Learn more about Newton's laws of motion and accelerated motion:
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The correct answer is A) decreases, because the gravitational force is inversely proportional to the square of the distance. In fact, the magnitude of the gravitational force between two object of mass M and m, at a distance d one from each other, is
where G is the gravitational constant. As can be seen from the formula, if the distance d between the two object increases, the intensity of the force decreases.