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zmey [24]
3 years ago
13

What is the velocity in meters per second of a runner who runs exactly 110 m toward the beach in 72 seconds.

Physics
2 answers:
alexdok [17]3 years ago
8 0
1.53 m/s towards the beach
KATRIN_1 [288]3 years ago
3 0

1.53 m/s toward the beach

Explanation:

The magnitude of the velocity of the runner is given by:

v=\frac{d}{t}

where

d is the displacement of the runner

t is the time taken

In this case, d=110 m and t=72 s, so the velocity of the runner is

v=\frac{110 m}{72 s}=1.53 m/s

Velocity is a vector, so it consists of both magnitude and direction: we already calculate the magnitude, while the direction is given by the problem, toward the beach.

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As we know that time period of simple pendulum is given as

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here we know that

T = 3.8 s

now from above equation we know that

T² = 4π² (L/g)

now on rearranging the above equation we will have

L = gT² / 4π²

now plug in all data into it

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7 0
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Suppose a wheel with a tire mounted on it is rotating at the constant rate of 3.33 times a second. A tack is stuck in the tire a
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Answer: 6.47m/s

Explanation:

The tangential speed can be defined in terms of linear speed. The linear speed is the distance traveled with respect to time taken. The tangential speed is basically, the linear speed across a circular path.

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velocity of the wheel = d/t

Since d is not given, we find d by using formula for the circumference of a circle. 2πr. Thus, V = 2πr/t

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V = 1.94/0.3

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The tangential speed of the tack is 6.47m/s

7 0
3 years ago
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<span>B. equal and in opposite directions</span>
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A plane traveling 40 m/s drops a box from a height of 186 m. Where does the box strike the ground relative to the point directly
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Explanation:

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3 years ago
A monatomic gas is adiabatically compressed to 0.250 of its initial volume. Do each of the following quantities change?
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Answer:

Given that

V2/V1= 0.25

And we know that in adiabatic process

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Vrms= √ 3RT/M

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Vrms2=√2.5= 1.6vrms1

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