What is the velocity in meters per second of a runner who runs exactly 110 m toward the beach in 72 seconds.
2 answers:
1.53 m/s toward the beach
Explanation:
The magnitude of the velocity of the runner is given by:
where
d is the displacement of the runner
t is the time taken
In this case, d=110 m and t=72 s, so the velocity of the runner is
Velocity is a vector, so it consists of both magnitude and direction: we already calculate the magnitude, while the direction is given by the problem, toward the beach.
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Answer:
a). M = 20.392 kg
b). am = 0.56 (block), aM = 0.28
(bucket)
Explanation:
a). We got N = mg cos θ,
f =
=
If the block is ready to slide,
T = mg sin θ + f
T = mg sin θ + .....(i)
2T = Mg ..........(ii)
Putting (ii) in (i), we get
M = 20.392 kg
b). .............(iii)
Here, l = total string length
Differentiating equation (iii) double time w.r.t t, l, h and h' are constants, so
.....................(iv)
We got, N = mg cos θ
∴
................(v)
Mg - 2T = M
(from equation (iv))
.....................(vi)
Putting (vi) in equation (v),
Using equation (iv), we get,
