What is the velocity in meters per second of a runner who runs exactly 110 m toward the beach in 72 seconds.
2 answers:
1.53 m/s toward the beach
Explanation:
The magnitude of the velocity of the runner is given by:
where
d is the displacement of the runner
t is the time taken
In this case, d=110 m and t=72 s, so the velocity of the runner is
Velocity is a vector, so it consists of both magnitude and direction: we already calculate the magnitude, while the direction is given by the problem, toward the beach.
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Answer:
The maximum amplitude () will be 7.96 V.
Explanation:
We know, for distortion free operation, the slew rate (S) of an OPAMP is written as
where '' is the highest frequency signal.
Therefore, from the above equation we can write,