1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Helga [31]
3 years ago
11

A passenger in a helicopter traveling upwards at 15 m/s accidentally drops a package out the window. If it takes 15 seconds to r

each the ground, how high to the nearest meter was the helicopter when the package was dropped?
Physics
1 answer:
Alexeev081 [22]3 years ago
8 0

Answer:

The helicopter was 1103.63 meters high when the package was dropped.

Explanation:

We consider positive speed as a downward movement

y: height (m)

t: time (s)

v₀: initial speed (m/s)

Δy = v₀t + \frac{1}{2}gt²

Δy= 15\frac{m}{s}×15 s + \frac{1}{2}×9.81\frac{m}{s^{2} }×(15 s)²

Δy= 1103.63 m

You might be interested in
Which statement is true of gravity?
o-na [289]

Answer:

B is the answers for the question

3 0
2 years ago
a car advertisement states that a certain car can accelerate from rest to 70km/h in 7 seconds. find the cars acceleration
ELEN [110]
<span>a = (v2 - v1)/t= acceleration formula

a = (70 - 0)/7
a = 10 km/hr/sec
-----
It's better to use as few units as possible.
10 km/hr = 10 km*1000 m/km/(1 hr*3600 sec/hr) = 25/9 m/sec
a= 25/9 m/sec/se</span>
4 0
3 years ago
PLEASE NEED THIS QUICKLY
saw5 [17]

The potential energy of the block is A) 490 J

Explanation:

The potential energy of an object is the energy possessed by the object due to its position in the gravitational field.

It is calculated as follows:

PE=mgh

where

m is the mass of the object

g is the acceleration due to gravity

h is the height of the object above the ground

For the block in this problem, we have:

m = 10 kg

g=9.8 m/s^2

h = 5 m

Therefore, its potential energy is:

PE=(10)(9.8)(5)=490 J

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

3 0
3 years ago
What law describes light
Darina [25.2K]

The law of reflection

6 0
3 years ago
In terms of saturation (unsaturated, saturated, super-saturated). How would you classify the following?
miskamm [114]

<u>Answer:</u>

<em>1. A NaCl solution with a concentration of 50g/100mL of water at 40°C:</em> The NaCl solution with a given concentration is saturated at this temperature .As the temperature increases the solution will more dissolves.

<em>2. A sugar solution with a concentration of 200g/100mL of water at 40°C: </em>The sugar solution with a given concentration is saturated at this temperature. As the temperature increases the solution will more dissolves.

<em>3. A sugar solution with a concentration of 240g/100mL of water at 40°C:</em> The sugar solution with a given concentration is saturated at given temperature.

7 0
3 years ago
Other questions:
  • Two identical, thin rods, each with mass m and length L, are joined at right angles to form an L-shaped object. This object is b
    7·2 answers
  • what Karl Kraus meant by the thought? "You'd be surprised how hard it is to translate an action into thought"
    14·1 answer
  • I'm a given chemical reaction, the energy of the products is less than the energy of the reactants. Which statement is true for
    14·2 answers
  • Questionson cell arrangement
    8·1 answer
  • 0.25-kg block oscillates on the end of a spring with a spring constant of 200 N/m. If the oscillations is started by elongating
    14·1 answer
  • A dielectric material is inserted between the charged plates of a parallel-plate capacitor. Do the following quantities increase
    12·2 answers
  • How and why dose air pressure change with altitude in the atmosphere
    14·1 answer
  • I don’t get how to answer the questions.
    12·1 answer
  • PLZZ IF ANYONE KNOWS SCIENCE HELP ME PLZ I this is so confusing :(
    12·2 answers
  • Vad händer när man värmer gaser? ​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!