Question

A passenger in a helicopter traveling upwards at 15 m/s accidentally drops a package out the window. If it takes 15 seconds to reach the ground, how high to the nearest meter was the helicopter when the package was dropped?

Answer 1

Answer:

The helicopter was 1103.63 meters high when the package was dropped.

Explanation:

We consider positive speed as a downward movement

y: height (m)

t: time (s)

v₀: initial speed (m/s)

Δy = v₀t + $\frac{1}{2}$gt²

Δy= 15$\frac{m}{s}$×15 s + $\frac{1}{2}$×9.81$\frac{m}{s^{2} }$×(15 s)²

Δy= 1103.63 m