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sergejj [24]
3 years ago
6

I what is the resistance of

Physics
1 answer:
Lynna [10]3 years ago
3 0
The resistance of a conductor is given by:
R= \frac{\rho L}{A}
where
\rho is the resistivity of the material
L is the length of the conductor
A is its cross-sectional area

We can use this formula to solve both parts of the problem.

a) The length of the copper wire is L=1.0 m. Its diameter is d=0.50 mm, so its radius is 
r= \frac{d}{2}=0.25 mm=0.25 \cdot 10^{-3} m
And its cross-sectional area is
A=\pi r^2 = \pi (0.25 \cdot 10^{-3}m)^2 = 1.96 \cdot 10^{-7} m^2
The copper resistivity is \rho=1.68 \cdot 10^{-8} \Omega m, therefore the resistance of this piece of wire is
R= \frac{\rho L}{A}= \frac{(1.68 \cdot 10^{-8} \Omega m)(1.0 m)}{1.96 \cdot 10^{-7} m^2}=  8.57 \cdot 10^{-2} \Omega

b) The length of this piece of iron is L=10 cm=0.10 m. Its cross-sectional size is L=1.0 mm=0.001 m, so its cross-sectional area is
A=L^2 = (0.001 m)^2 =1 \cdot 10^{-6}m^2
The iron resistivity is \rho = 9.71 \cdot 10^{-8} \Omega m, therefore the resistance of this piece of wire is
R= \frac{\rho L}{A}= \frac{(9.71 \cdot 10^{-8} \Omega m)(0.10 m)}{1.0 \cdot 10^{-6} m^2}=9.71 \cdot 10^{-3} \Omega

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