Answer:
Explanation:
a)8*7.2=57.6 cm^2
b)8*8=64 m^2
c)3.4*5.2=17.68 mm*2
d)2.6*4.7=12.22 m^2
e)13*5.1=13*5100=66300 m^2
Answer:
option c. 21.0
Explanation:
It was given that to find 3 significant figures. So the answer is 21.0
Answer:
The latent heat of vaporization of water is 2.4 kJ/g
Explanation:
The given readings are;
The first (mass) balance reading (of the water) in grams, m₁ = 581 g
The second (mass) balance reading (of the water) in grams, m₂ = 526 g
The first joulemeter reading in kilojoules (kJ), Q₁ = 195 kJ
The second joulemeter reading in kilojoules (kJ), Q₂ = 327 kJ
The latent heat of vaporization = The heat required to evaporate a given mass water at constant temperature
Based on the measurements, we have;
The latent heat of vaporization = ΔQ/Δm
∴ The latent heat of vaporization of water = (327 kJ - 195 kJ)/(581 g - 526 g) = 2.4 kJ/g
The latent heat of vaporization of water = 2.4 kJ/g
Answer:
The gplanet is 0.193 m/s^2
Explanation:
The speed of the pulse is:
where
m=mass of the wire=4 g= 4x10^-3 kg
M=mass of the object= 3 kg
Replacing values:
Answer: cool, dry air meets warm, moist air
Explanation:
Just did the test, it was correct