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3 years ago

Question is in the pic

Physics

2 answers:

mihalych1998 [28]3 years ago

8 0

The answer is C in the picture.

Anton [14]3 years ago

4 0

Answer: The answer is A

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Which of the following is considered a calm area close to the equator resulting in little to no wind?

solong [7]

<h2>Right answer: Doldrums</h2>

These are also called zones of equatorial calm and it is due a climatic phenomenon that is placed near the Earth equator, attributed to the soft winds, that are called calm winds as well; accompanied by systems of abundant rains and heat.

In this area periods of great calm occur when the winds virtually disappear completely, trapping the sailing ships for long periods (days or weeks). This is why the term doldrum became popular as a colloquial expression in the eighteenth century, to refer to "the caprice of the wind that slows down the navigation to sail".

The zone is located in the place where two trade winds meet, this means the trade winds of the northern hemisphere converge with those of the southern hemisphere, that is why this region is related to the intertropical convergence zone.

5 0

4 years ago

A soccer goal is 2.44 m high. A player kicks the ball at a distance 13 m from the goal at an angle of 40°, and the ball just hit

Vera_Pavlovna [14]

Let v denote the initial speed of the ball. The ball's position at time t is given by the vector

$\mathbf r(t)=v\cos40^\circ\,t\,\mathbf i+\left(v\sin40^\circ\,t-\dfrac g2t^2\right)\,\mathbf j$

where g is the acceleration due to gravity with magnitude 9.80 m/s^2.

The ball reaches the goal 13 m away at time t such that

$10\,\mathrm m=v\cos40^\circ t\implies t=\dfrac{10\,\mathrm m}{v\cos40^\circ}$

at which point it attains a height of 2.44 m, so that

$2.44\,\mathrm m=v\sin40^\circ\left(\dfrac{10\,\mathrm m}{v\cos40^\circ}\right)-\dfrac g2\left(\dfrac{10\,\mathrm m}{v\cos40^\circ}\right)^2$

$2.44\,\mathrm m=(10\,\mathrm m)\tan40^\circ-\dfrac12\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)\left(\dfrac{100\,\mathrm m^2}{v^2\cos^240^\circ}\right)$

$\implies\boxed{v\approx3.75\dfrac{\rm m}{\rm s}}$

6 0

4 years ago

Imagine that you’re observing a collision. Which action would allow you to determine whether the collision is inelastic?

Thepotemich [5.8K]

The answer is B;) in plato

3 0

3 years ago

Read 2 more answers

Question is in the picture

Svetradugi [14.3K]

the more pressure put on the string, the more frequency and higher pitch.

4 0

4 years ago

If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 39m/s, how far would she

loris [4]

Answer:

She would travel 175.5 m in the same amount of time

Explanation:

Here is the complete question:

Seven bicyclist are racing. Each bicyclist rides for 9s. If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 39m/s, how far would she travel during the race in the same amount of time)?

Explanation:

To determine how far she would travel in the same amount of time, that is the distance she would cover in the same amount of time

From the question,

The bicyclist has an initial velocity of zero

That is, u = 0 m/s

and a final velocity of 39 m/s

That is, v = 39 m/s

Each bicyclist rides for 9s,

She also traveled for the same amount of time

that is, t = 9s

To determine the distance,

From one of the equations of motion for linear motion

s = $\frac{1}{2}$ t(u + v)

Then

s = $\frac{1}{2}$ (9)(0+39)

s = 4.5 (39)

s = 175.5 m

Hence, she would travel 175.5 m in the same amount of time

5 0

4 years ago