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Elena L [17]
1 year ago
7

How many grams of NCI3 are in 4.00 moles of NC13?

Chemistry
1 answer:
TEA [102]1 year ago
5 0

The mass of NCl3 in 4.00 moles of NCl3 is 481.44 grams

Mole is defined as the amount of the substance containing the same number of discrete entities (atoms, molecules, ions, etc) as there are atoms in a sample of pure 12C weighing exactly 12g. The number of particles present in one mole of any substance =Avogadro Number=6.

The formula for number mole is given as:

Number of moles =  <u>Mass of the substance </u> ; Now substituting the values

                                   Molar mass

⇒ 4.00 =  <u>x        </u>                       [Molar mass of NCl3 = 120.36]

               120.36

⇒ x = 4.00 × 120.36

⇒ x = 481.44 grams

Therefore the mass of NCl3 is 481.44 grams

To know more about mole concept

brainly.com/question/23059935

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When solutions of sodium sulfide and copper(ii) sulfate are mixed, a precipitate of copper(ii) sulfide is formed. The net ionic equation for this reaction is Cu⁺² (aq) + S⁻² (aq) → CuS (s).

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now first write the balanced chemical equation

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Now write the net ionic equation

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So the net ionic equation is

Cu⁺² (aq) + S⁻² (aq) → CuS (s)

Thus from the above conclusion we can say that When solutions of sodium sulfide and copper(ii) sulfate are mixed, a precipitate of copper(ii) sulfide is formed. The net ionic equation for this reaction is Cu⁺² (aq) + S⁻² (aq) → CuS (s).

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