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Elena L [17]
1 year ago
7

How many grams of NCI3 are in 4.00 moles of NC13?

Chemistry
1 answer:
TEA [102]1 year ago
5 0

The mass of NCl3 in 4.00 moles of NCl3 is 481.44 grams

Mole is defined as the amount of the substance containing the same number of discrete entities (atoms, molecules, ions, etc) as there are atoms in a sample of pure 12C weighing exactly 12g. The number of particles present in one mole of any substance =Avogadro Number=6.

The formula for number mole is given as:

Number of moles =  <u>Mass of the substance </u> ; Now substituting the values

                                   Molar mass

⇒ 4.00 =  <u>x        </u>                       [Molar mass of NCl3 = 120.36]

               120.36

⇒ x = 4.00 × 120.36

⇒ x = 481.44 grams

Therefore the mass of NCl3 is 481.44 grams

To know more about mole concept

brainly.com/question/23059935

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Answer:

[F^-]_{max}=4x10{-3}\frac{molF^-}{L}

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In this case, for the described situation, we infer that calcium reacts with fluoride ions to yield insoluble calcium fluoride as shown below:

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