Answer:
Final mass of Argon= 2.46 kg
Explanation:
Initial mass of Argon gas ( M1 ) = 4 kg
P1 = 450 kPa
T1 = 30°C = 303 K
P2 = 200 kPa
k ( specific heat ratio of Argon ) = 1.667
assuming a reversible adiabatic process
<u>Calculate the value of the M2 </u>
Applying ideal gas equation ( PV = mRT )
P₁V / P₂V = m₁ RT₁ / m₂ RT₂
hence : m2 = P₂T₁ / P₁T₂ * m₁
= (200 * 303 ) / (450 * 219 ) * 4
= 2.46 kg
<em>Note: Calculation for T2 is attached below</em>
Explanation:
Thermodynamics system :
Thermodynamics system is a region or space in which study of matters can be done.The system is separated from surroundings by a boundary this boundary maybe flexible or fixed it depends on situations.The out side the system is called surroundings.
Generally thermodynamics systems are of three types
1.Closed system(control mass system)
Only energy transfer take place ,no mass transfer take place.
2.Open system(control volume system)
Both mass as well as energy transfer take place.
3.Isolated system
Neither mass or nor energy transfer take place.
At steady state ,property is did not changes with respect to time.
Explanation:
commands to be and function arguments
Answer:
Part a : The SI unit of σ is Pascal.
Part b : The pressure is 414.28 psi.
Explanation:
Part a
The equation is given as
As per the dimensional analysis
![M=[N-m]\\y=[m]\\l=[m^4]](https://tex.z-dn.net/?f=M%3D%5BN-m%5D%5C%5Cy%3D%5Bm%5D%5C%5Cl%3D%5Bm%5E4%5D)
So the equation becomes
![\sigma =\frac{[N-m][m]}{[m^4]}\\\sigma =\frac{[N][m^2]}{[m^4]}\\\sigma =\frac{[N]}{[m^{4-2}]}\\\sigma =\frac{[N]}{[m^{2}]}\\](https://tex.z-dn.net/?f=%5Csigma%20%3D%5Cfrac%7B%5BN-m%5D%5Bm%5D%7D%7B%5Bm%5E4%5D%7D%5C%5C%5Csigma%20%3D%5Cfrac%7B%5BN%5D%5Bm%5E2%5D%7D%7B%5Bm%5E4%5D%7D%5C%5C%5Csigma%20%3D%5Cfrac%7B%5BN%5D%7D%7B%5Bm%5E%7B4-2%7D%5D%7D%5C%5C%5Csigma%20%3D%5Cfrac%7B%5BN%5D%7D%7B%5Bm%5E%7B2%7D%5D%7D%5C%5C)
As the dimensions are of pressure so the SI unit of σ is Pascal.
Part b
Pressure in US customary base units is given in psi so
So
So the pressure is 414.28 psi.
