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3 years ago

8

A metal ball rolls from rest at Point A down the track to Point E as shown below.

1 answer:

Tju [1.3M]3 years ago

8 0

Answer:

Explanation:

Velocity is at its greatest when kinetic energy is at its max which is when all the ball's energy has been transformed from potential energy to kinetic energy which is at the lowest point in its travels (assuming the ball is rolling down a ramp). You have no picture here so this answer is a general one, not a specific one.

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andrezito [222]

Answer:

1.To get your team to 25 points each period by serving, spiking, and setting the ball

2. A gymnasium with volleyball court markings, a net, a volleyball

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3 years ago

Which of the following is an environmental consequence of nuclear energy?

Alex Ar [27]

It is letter b which is Global Warming

4 0

3 years ago

A bat emits a sound at a frequency of 30.0 kHz as it approaches a wall. The bat detects beats such that the frequency of the ech

Alex

Answer:

The speed of the bat is 5.02 m/s.

Explanation:

Given that,

Frequency = 30.0 kHz

Frequency of echo = 900 Hz

We need to calculate the frequency

Using formula of beat frequency

$f_{b}=f_{1}-f_{2}$

Put the value into the formula

$900=f_{1}-30\times10^{3}$

$f_{1}=900+30000$

$f_{1}=30900\ Hz$

We need to calculate the speed of the bat

Using Doppler equation

$f_{apr}=f\times(\dfrac{v_{sound}+v_{observer}}{v_{s}-v_{source}})$

Put the value into the formula

$30900=30000\times(\dfrac{340+v_{bat}}{340-v_{bat}})$

$\dfrac{30900}{30000}=\dfrac{340+v_{bat}}{340-v_{bat}}$

$1.03=\dfrac{340+v_{bat}}{340-v_{bat}}$

$340\times1.03-340=v_{b}+1.03v_{b}$

$10.2=2.03v_{bat}$

$v_{bat}=\dfrac{10.2}{2.03}$

$v_{bat}=5.02\ m/s$

Hence, The speed of the bat is 5.02 m/s.

6 0

3 years ago

A series RL circuit includes a 6.05 V 6.05 V battery, a resistance of R = 0.655 Ω , R=0.655 Ω, and an inductance of L = 2.55 H.

Ivenika [448]

Answer:

The induced emf 1.43 s after the circuit is closed is 4.19 V

Explanation:

The current equation in LR circuit is :

$I=\frac{V}{R} (1-e^{\frac{-Rt}{L} })$ .....(1)

Here I is current, V is source voltage, R is resistance, L is inductance and t is time.

The induced emf is determine by the equation :

$V_{e}=L\frac{dI}{dt}$

Differentiating equation (1) with respect to time and put in above equation.

$V_{e}= L\times\frac{V}{R}\times\frac{R}{L}e^{\frac{-Rt}{L} }$

$V_{e}=Ve^{\frac{-Rt}{L} }$

Substitute 6.05 volts for V, 0.655 Ω for R, 2.55 H for L and 1.43 s for t in the above equation.

$V_{e}=6.05e^{\frac{-0.655\times1.43}{2.55} }$

$V_{e}=4.19\ V$

5 0

3 years ago

a wall of glass 2cm thickhas inside temperature of 30°C,outside temperature of15°C.how much heat is flowing through the glass(k=

kenny6666 [7]

Answer:46.5

Explanation:is the topical formula of F= 30x+15

5 0

4 years ago