A metal ball rolls from rest at Point A down the track to Point E as shown below.
1 answer:
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Explanation:
It is given that,
Mass of the tackler, m₁ = 120 kg
Velocity of tackler, u₁ = 3 m/s
Mass, m₂ = 91 kg
Velocity, u₂ = -7.5 m/s
We need to find the mutual velocity immediately the collision. It is the case of inelastic collision such that,
v = -1.5 m/s
Hence, their mutual velocity after the collision is 1.5 m/s and it is moving in the same direction as the halfback was moving initially. Hence, this is the required solution.
Answer : The distance of the image from the lens is, -42 cm
The height of the image is, 35 cm
Solution :
First we have to calculate the image distance.
Formula used :
where,
f = focal length = 7 cm
p = object distance = 6 cm
q = image distance = ?
Now put all the given values in the above formula, we get the distance of the image from the lens.
Therefore, the distance of the image from the lens is, 42 cm and the negative sign indicates that the image is virtual.
Now we have to calculate the height of the image.
Formula used :
where,
h = height of object = 5 cm
h' = height of image = ?
Now put all the given values in this formula, we get the height of the image.
Therefore, the height of the image is, 35 cm and the negative sign indicates that the image is inverted.