What are the 5 steps in the process of air circulation in order

(b) suppose two telephone poles are 40 ft apart and the length of the wire between the poles is 41 ft. if the lowest point of th

lakkis [162]

Refer to the diagram shown below.

The suspended wire is in the shape of a parabola defined by the equation
y = ax²
where a = a positive constant.
The derivative of y with respect to x is y' = 2ax.

The vertex is at (0,0) and the line of symmetry is x = 0.
The suspended length is 41 ft, therefore half the suspended length is 20.5 ft.
The length between x = 0 and x = 20 is given by
$\int _{0}^{20} \sqrt{1+[y'(x)]^{2}} \, dx = \int_{0}^{20} \sqrt{1+4a^{2}x^{2}} \, dx =20.5$

Because we do not know the value of a, we shall find it numerically.
Define the function
$f(a) = \int _{0}^{20} \sqrt{1+4a^{2}x^{2}} \, dx - 20.5 = 0$
The plot for f(a) versus a yields an approximate solution (from Matlab) of a = 0.01 (shown in the figure).

Therefore
y = 0.01x²
When x = 20 ft, h = 0.01(400) = 4 ft
Because the vertex of the parabola is 19 ft above ground, the support points for the wire are 19 + h = 23 ft above ground.

Answer: 23.00 ft

7 0

3 years ago

QUESTION 10

Vera_Pavlovna [14]

Smaller-sized bags, I would think. There is less in the bags so she has less to eat. She would excersise a small bag off faster than a big bag.

5 0

3 years ago

Newton's three laws of motion

AfilCa [17]

Answer:

The third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal force on object A. Notice that the forces are exerted on different objects.

Explanation:

4 0

3 years ago

Read 2 more answers

During which changes of state do atoms that cannot move past one another become free to move

Grace [21]

Answer:

The correct answer is from solid to liquid (melting), and from liquid to gas (sublimation).

Explanation:

In the solid-state the energy of the molecules is low, so the molecules will have very little movement. In the liquid state, molecules have a higher level of energy, and as they move from solid to liquid state they acquire greater mobility. In a gaseous state, the energy level is very high and the molecules have a higher degree of mobility.

This can also be described through the predominant molecular forces in each state. The cohesion forces present in solids are stronger than those of repulsion. In the liquid state, the repulsion and attraction forces are balanced. Finally, in the gaseous state, the repulsive forces between the molecules predominate.

Have a nice day!

4 0

3 years ago

Jake is helping Fin push a box at a constant velocity up an incline that makes an angle of 30.0° above the horizontal by applyin

andre [41]

Given data

The angle of inclination of the plane is theta = 30 degree

The applied force in the inclined plane is F = 94 N

The distance moved in the inclined plane is d = 2.30 m

The coefficient of kinetic friction is u_k = 0.280

The free-body diagram of the above configuration is shown below:

Here, the normal reaction force on the box is N, the acceleration due to gravity is denoted as g, the friction force on the box is F_f, and the mass of the box is denoted as m.

(a)

The expression for the work done by the pushing force is given as:

$W=Fd$

Substitute the value in the above equation.

$\begin{gathered} W=94\text{ N}\times2.30\text{ m} \\ W=216.2\text{ J} \end{gathered}$

Thus, the work done by the pushing force is 216.2 J.

(b)

The box is moving at the constant velocity, therefore, the pushing force will be equal to the frictional force and the component of the gravitational force in the inclined plane.