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1 year ago

He pushed the car beyond the tollgate and poured a bucket of water on the smoking hood. previousnext

Physics

1 answer:

Irina-Kira [14]1 year ago

6 0

He moved the car past the toll booth and doused the flaming hood with water using the comma.

<h3>What makes water vital to life?</h3>

Chemical processes are necessary for life to produce energy, grow, and eliminate waste. Water is a liquid that facilitates the chemistry of life. Additionally, because it is a polar molecule, most other molecules can dissolve in it. As a result, we refer to water as a "solvent".

<h3>How does science define water?</h3>

Water is a substance that exists in gaseous, fluid, and solid phases and is made up of the molecular elements both hydrogen and oxygen. One of the prevalent and necessary substances is it. a liquid that is flavorless and odorless at ambient temperature.

To know more about water visit:

brainly.com/question/11885065

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Bromine is a liquid at room temperature. The volume of a sample of bromine is measured in a 50 beaker and a 100 ml beaker. How w

Stells [14]

Answer:

The comparisons are;

The height of the bromine in the 50 ml beaker will be twice that of the 100 ml beaker

The measurement of the volume with the 50 ml beaker will be more accurate than the measurement taken with the 100 ml beaker, because the differences in the height of the bromine in the 50 ml beaker is more obvious than the differences measured with the 100 ml beaker.

The actual volume of bromine in both beakers will be equivalent

Explanation:

The properties of a liquid are;

1) The volume of a liquid is relatively fixed at conditions that are suitable for it to remain in the liquid state compared to the volume occupied by a gas

2) A liquid will assume the shape of a container in which it is placed

3) The surface of a liquid in a container is flat due in order that the attractive forces between the molecules of the liquid at the surface and inside the body of the liquid should be in equilibrium

Therefore, given that the volume of the Bromine is measured in 50 ml beaker and a 100 ml beaker, there will be differences in the measured height of the same volume of bromine in each beaker.

5 0

3 years ago

A rock is thrown upward with a velocity of 18 meters per second from the top of a 38 meter high cliff, and it misses the cliff o

Roman55 [17]

The rock would be at a point 12 m from water at a time <u>4.8 s</u>.

Take the origin of the coordinate system at the top of the cliff. It is thrown upwards with a velocity u. When the rock is at a point 12 m from water, calculate the vertical displacement of the rock from the origin.

$y= -38m- (-12 m)=-26 m$

Use the equation of motion,

$y=ut +\frac{1}{2} at^2$

The rock falls under the acceleration due to gravity, directed down wards.

Substitute 18 m/s for u, -26 m for y and -9.8 m/s² for a=g.

$y=ut +\frac{1}{2} at^2\\ (-26 m)=(18m/s)t+\frac{1}{2}(-9.8m/s^2)t^2$

Solve the quadratic equation for t.

$t=\frac{(18m/s)(+/-)\sqrt{(18m/s)^2-4(4.9m/s^2)(-26m)} }{2(4.9m/s^2)}$

Taking only the positive value,

$t=\frac{(18 m/s)+(28.87 m/s)}{9.8 m/s^2)} \\ t=4.78 s$

After a time of <u>4.8 s</u> the rock would be at a distance of 12 m from water.

8 0

3 years ago

A geosynchronous satellite orbits Earth at a distance of 42,250 km from the center of Earth and has a period of 1 day. What is t

yan [13]

Answer:

The centripetal acceleration of the satellite is $a=0.22\ m/s^2$ .

Explanation:

Given that,

The distance covered by a geosynchronous satellite, d = 42250 km

The time taken by the satellite to covered distance, t = 1 day = 24 hours

Since, 24 hours = 86400 seconds

Let v is the speed of the satellite. It is given by the total distance divided by total time taken such that :

$v=\dfrac{d}{t}$

$v=\dfrac{2\pi d}{t}$

$v=\dfrac{2\pi\times 42250 \times 10^3}{86400 }$

v = 3072.5 m/s

The centripetal acceleration of the satellite is given by :

$a=\dfrac{v^2}{d}$

$a=\dfrac{(3072.5)^2}{42250 \times 10^3}$

$a=0.22\ m/s^2$

So, the centripetal acceleration of the satellite is $a=0.22\ m/s^2$ . Hence, this is the required solution.

7 0

3 years ago

Convert 45 hours into days

xenn [34]

1.875 is your answer

3 0

3 years ago

The intensity at distance from a spherically symmetric sound source is 100 W/m2. What is the intensity at five times this distan

ss7ja [257]

To solve this problem it is necessary to apply the concepts related to intensity as a function of power and area.

Intensity is defined to be the power per unit area carried by a wave. Power is the rate at which energy is transferred by the wave. In equation form, intensity I is

$I = \frac{P}{A}$