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3 years ago

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Physics

1 answer:

OLga [1]3 years ago

6 0

Answer:B. NET force: 2 resultant motion: left

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C. Net force: 3 Resultant motion: Left

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D. Net Force: 7 Resultant motion: right

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E. Net Force:0 resultant motion: NO MOTION

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F. NET Force: 3 resultant motion: Down

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G. NET FORCE: 10 resultant motion: up

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H. Net force: 3 Resultant motion: left

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I. Net force: 50 Resultant motion: right

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J. NET FORCE: 75 Resultant motion: down

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K. Net force :200 Resultant motion: Right

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L. Net force: 0 resultant motion:No motion

Explanation:

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Mars passes closer to earth than jupiter does, but with an earth-based telescope it is easier to see details on jupiter than on

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3 years ago

Which expression represents the sum of 8 and twice a number<br> 8+n<br> 8+2n<br> 8×2n<br> 2×(8+n)

Lynna [10]

Answer:

8 + 2 n (second expression listed)

Explanation:

Since we don't know the number, we represent it with a letter (n).

Twice a number (two times that number) will therefore be: 2 n.

and the addition (sum) of 8 to such will lead to 8 + 2 n

The sum of 8 and twice a number is : 8 + 2 n

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3 years ago

The rate at which an object moves

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3 years ago

Read 2 more answers

A rod of 2.0-m length and a square (2.0 mm x 2.0 mm) cross section is made of a material with a resistivity of 6.0 x 10^-8 0.Ω.m

Ksju [112]

Answer:

Heat generated in the rod is 8.33 watts.

Explanation:

It is given that,

Length of rod, l = 2 m

Area of cross section, $A=2\ mm\times 2\ mm=4\ mm^2=4\times 10^{-6}\ m^2$

Resistivity of rod, $\rho=6\times 10^{-8}\ \Omega-m$

Potential difference, V = 0.5 V

The value of resistance is given by :

$R=\rho\dfrac{l}{A}$

$R=6\times 10^{-8}\ \Omega-m\times \dfrac{2\ m}{4\times 10^{-6}\ m^2}$

R = 0.03 ohms

Let H is the rate at which heat is generated in the rod . It is given by :

$\dfrac{H}{t}=I^2R$

Since, $I=\dfrac{V}{R}$

$\dfrac{H}{t}=\dfrac{V^2}{R}$

$\dfrac{H}{t}=\dfrac{(0.5)^2}{0.03}$

$\dfrac{H}{t}=8.33\ watts$

So, the at which heat is generated in the rod is 8.33 watts. Hence, this is the required solution.

8 0

4 years ago

57.0- g tennis ball is traveling straight at a player at 21.0 m/ s. The player volleys the ball straight back at 25.0 m/ s. If t

Yakvenalex [24]

Answer:43.7 N

Explanation:

Given

Mass of tennis ball is =57 gm

velocity of ball=21 m/s

The player volleys the ball straight back at 25 m/s(i.e. in opposite of initial direction)

time of contact=0.06 s

We know change in momentum $(\Delta P) =Impulse(Fdt)$

initial momentum $=57\times 10^{-3}\times 21$

final momentum $=-57\times 10^{-3}\times 25$

change in momentum

$\Delta P=57\times 10^{-3}\times 21-(-57\times 10^{-3}\times 25)$

$\Delta P=57\times 10^{-3}\times 46=2.622 kg-m/s$

Now 2.622 $=F_{avg}\times 0.06$

$F_{avg}=43.7 N$

4 0

3 years ago