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TiliK225 [7]
3 years ago
6

How does the kinetic molecular theory explain the behavior of gases?

Chemistry
1 answer:
WITCHER [35]3 years ago
5 0
Kinetic Molecular Theory<span> states that </span>gas<span> particles are in constant motion and exhibit perfectly elastic collisions. </span>Kinetic Molecular Theory<span> can be used to </span>explain<span>both Charles' and Boyle's Laws. The average </span>kinetic<span> energy of a collection of </span>gas<span>particles is directly proportional to absolute temperature only.</span>
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What is an electrolyte?
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A substance that can conduct electricity in solution

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Gold has a specific heat of 0.126 J/g.C. Copper has a specific heat of 0.386 J/g C. Which of the two metals would require more
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The copper, because its specific heat is higher, meaning it takes more heat (Joules) per gram to raise the temperature 1 degree Celsius.

Explanation:

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2 years ago
. how many lone pairs of electrons are present in the lewis structure of calcium sulfide?
miv72 [106K]
Answer:
            <u>Four</u>

Explanation:
                     Calcium Sulfide is an ionic compound made up of Ca²⁺ and S²⁻.
Ca²⁺ is formed as,

                                   Ca    →    Ca²⁺  +  2 e⁻

These two electrons are accepte by Sulfur as,

                                     S  +  2 e⁻    →    S²⁻

So, before accepting 2 electrons S was having six valence electrons, after accepting two electrons from Ca it has 8 electrons which are present in four pairs as shown below,

7 0
3 years ago
When exothermic reactions occur, ______________.
marusya05 [52]

Answer:

heat energy is released into the surrounding

3 0
1 year ago
A process at constant T and P can be described as spontaneous if ΔG &lt; 0 and nonspontaneous if ΔG &gt; 0. Over what range of t
creativ13 [48]

Answer:

Incomplete question, it is lacking the data it makes reference. The missing data from Chegg is:

                              2 SO3(g)   →          2 SO2(g) + O2(g)

ΔHf° (kJ mol-1)  -395.7                        -296.8

S° (J K-1 mol-1)  256.8                         248.2              205.1

ΔH° =  kJ

S° =  J K⁻¹

Explanation:

The method to solve this problem calls for the use of the Gibbs standard free energy change:

ΔG = ΔrxnH - TΔSrxn

We know a reaction is spontaneous when ΔG is < 0, so to answer this question we need to solve for the temperature, T, at which ΔG becomes negative.

Now as mentioned in the hint, we need to determine  ΔrxnH and ΔSrxn, which are given by

ΔrxnH = ∑ ν x ΔfHº products - ∑ ν x ΔfHº reactants

where  ν  is the stoichiometric coefficient in the balanced chemical equation.

For ΔS we have likewise

ΔrxnS =  ∑ ν x ΔSº products - ∑ ν x ΔSº reactants

Thus,

ΔrxnH(kJmol⁻¹) =  2 x (-296.8) - 2 x ( -395.7 ) = 197.8 kJ

ΔrxnS ( JK⁻¹) = 2 x 248.2 + 205.1 - 2 x 256.8 = 187.9 JK⁻¹ = 0.1879 kJK⁻¹

So ΔG kJ =  197.8 - T(0.1879)

and the reaction will become spontaneous when the term  T(0.1879)  becomes greater that 197.8,

0 = 197.8 - 0.1879 T  ⇒ T = 1052 K

so the reaction is spontaneous at temperatures greater than 1052 K (780 ºC)

4 0
3 years ago
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