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Effectus [21]
1 year ago
5

a car carrying a 80-kgkg test dummy crashes into a wall at 28 m/sm/s and is brought to rest in 0.10 ss. part a what is the magni

tude of the average force exerted by the seat belt on the dummy? express your answer to two significant figures and include the appropriate units
Physics
1 answer:
iragen [17]1 year ago
7 0

The magnitude of the average force exerted by the seat belt on the dummy is 224N .

<h3>What is an average force ?</h3>

The average force is the force produced by an object moving over a specific period of time at a given rate of speed, or velocity. This velocity is not instantaneous or precisely measured, as the word "average" indicates.

<h3>Briefing:</h3>

mass of the dummy (m) = 80kg

velocity of the dummy (v) = 28 m/s

time (t) = 10 seconds

Average force exerted (F)

To calculate the average force;

According to the formula;

F = (m × v) ÷ t

Where;

F represents the force exerted

m represents the mass of the dummy

v represents the velocity

t represents the time

F = m * v/t

F = 80 *28/10

F = 224

F = 224 N

The force exerted by the seat belt on the dummy is 224N .

To know more about Average force visit:

brainly.com/question/24704743

#SPJ4

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acc. = 4-(-6) /5= 10/5=2 m/s^2

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3 years ago
When you apply a horizontal force of 76 N to a block, the block moves across the floor at a constant speed ().When you apply a f
elena-s [515]

Answer:

Explanation:

When we apply a horizontal force of 76 N to a block, the block moves across the floor at a constant speed. So net force on the block is zero .

It implies that a force ( frictional ) acts on it which is equal to 76 N in opposite direction ( friction )

When we apply  a greater force on it it starts moving with acceleration .

This time kinetic friction acts on it due to rough ground equal to 76 N .This is limiting friction ( maximum friction )

Net force on the body in later case

= 89 - 76

= 13 N

Force by ground on the block in horizontal direction = 76 N ( FRICTIONAL FORCE )

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3 0
4 years ago
A 1560-kilogram truck moving with a speed of 28.0 m/s runs into the rear end of a 1070-kilogram stationary car. If the collision
Nimfa-mama [501]

Answer:

Δ KE =  249158.6 kJ  

Explanation:

given data

Truck mass  M =  1560 Kg

Truck initial speed, u = 28 m/s

mass of car m = 1070 Kg

initial speed of car u1 = 0 m/s

solution

first we get here final speed by using conservation of momentum  that is express as

Mu = (M+m) V     .......................1

put here  value we get

1560 × 28 = (1560 + 1070 ) V

solve it we get

final speed V = 16.60 m/s

and

Change in kinetic energy  will be here

Δ KE =   \frac{1}{2} Mu^2 - \frac{1}{2}(M+m)V^2         .................2

put here value and we get

 Δ KE = \frac{1}{2}\times 1560\times 28^2 - \frac{1}{2}\times (1560 + 1070)\times 16.60^2  

solve it we get

Δ KE =  249158.6 kJ  

6 0
3 years ago
Stio
Ainat [17]

The true statements about magnetic fields and forces will be A,D and E.

<h3>What is a magnet?</h3>

An iron piece,alloy, or other substance with its constituent atoms arranged in such a way that it shows magnetism qualities,

The function of the magnet is attracting other iron-containing objects or aligning itself in a magnetic field.

There are two poles of the magnet;

1. North Pole.

2. South Pole.

The same poles repel each other, while the opposite poles attract each other. In a sense, south-south and north-north repel. While the north-south and the south-north attract each other.

The correct statements are;

(A). The north pole attracts the south pole of a magnet.

(D)Forces caused by magnetic fields are weaker farther from the magnet.

(E)Magnetic forces can act on an object even if the object isn't touching the magnet.

Hence, the true statements about magnetic fields and forces will be A,D and E.

To learn more about the magnet, refer to the link;

brainly.com/question/13026686

#SPJ1

3 0
2 years ago
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