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Effectus [21]
1 year ago
5

a car carrying a 80-kgkg test dummy crashes into a wall at 28 m/sm/s and is brought to rest in 0.10 ss. part a what is the magni

tude of the average force exerted by the seat belt on the dummy? express your answer to two significant figures and include the appropriate units
Physics
1 answer:
iragen [17]1 year ago
7 0

The magnitude of the average force exerted by the seat belt on the dummy is 224N .

<h3>What is an average force ?</h3>

The average force is the force produced by an object moving over a specific period of time at a given rate of speed, or velocity. This velocity is not instantaneous or precisely measured, as the word "average" indicates.

<h3>Briefing:</h3>

mass of the dummy (m) = 80kg

velocity of the dummy (v) = 28 m/s

time (t) = 10 seconds

Average force exerted (F)

To calculate the average force;

According to the formula;

F = (m × v) ÷ t

Where;

F represents the force exerted

m represents the mass of the dummy

v represents the velocity

t represents the time

F = m * v/t

F = 80 *28/10

F = 224

F = 224 N

The force exerted by the seat belt on the dummy is 224N .

To know more about Average force visit:

brainly.com/question/24704743

#SPJ4

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The acceleration of the first block (4 kg) is -9.8 m/s².

The given parameters:

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The net force on the system of the two blocks is calculated as follows;

m_2 g - T = m_1 a

where;

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m_2 g - m_1 g = m_1 a\\\\a = \frac{m_2 g - m_1g}{m_1} \\\\a = \frac{g(m_2 - m_1)}{m_1} \\\\a = \frac{9.8(2-4)}{2} \\\\a = -9.8 \ m/s^2

Thus, the acceleration of the first block (4 kg) is -9.8 m/s².

Learn more about net force on two connected blocks here: brainly.com/question/13539944

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What is the mass of a crate if a net force of 12 N gives the crate an acceleration of 0.20 m/s2?
Veseljchak [2.6K]
A :-) for this question , we should apply
F = ma
Given - F = 12 N
a = 0.20 m/s^2
Solution -
F = ma
12 = m x 0.20
m = 12 by 0.20
m = 60 kg

.:. The mass is 60 kg.
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The decimal point is placed after two digits starting from the end. For each decimal place, we can write the number divided by 100.

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Divide the numerator and denominator by 2:

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There is no other common factor between numerator and denominator other than 1. Hence, it is the reduced form.




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