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Effectus [21]
1 year ago
5

a car carrying a 80-kgkg test dummy crashes into a wall at 28 m/sm/s and is brought to rest in 0.10 ss. part a what is the magni

tude of the average force exerted by the seat belt on the dummy? express your answer to two significant figures and include the appropriate units
Physics
1 answer:
iragen [17]1 year ago
7 0

The magnitude of the average force exerted by the seat belt on the dummy is 224N .

<h3>What is an average force ?</h3>

The average force is the force produced by an object moving over a specific period of time at a given rate of speed, or velocity. This velocity is not instantaneous or precisely measured, as the word "average" indicates.

<h3>Briefing:</h3>

mass of the dummy (m) = 80kg

velocity of the dummy (v) = 28 m/s

time (t) = 10 seconds

Average force exerted (F)

To calculate the average force;

According to the formula;

F = (m × v) ÷ t

Where;

F represents the force exerted

m represents the mass of the dummy

v represents the velocity

t represents the time

F = m * v/t

F = 80 *28/10

F = 224

F = 224 N

The force exerted by the seat belt on the dummy is 224N .

To know more about Average force visit:

brainly.com/question/24704743

#SPJ4

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3 years ago
Two boxers are fighting. Boxer 1 throws his 5 kg fist at boxer 2 with a speed of 9 m/s.
Sladkaya [172]

Answer:

0.001 s

Explanation:

The force applied on an object is equal to the rate of change of momentum of the object:

F=\frac{\Delta p}{\Delta t}

where

F is the force applied

\Delta p is the change in momentum

\Delta t is the time interval

The change in momentum can be written as

\Delta p=m(v-u)

where

m is the mass

v is the final velocity

u is the initial velocity

So the original equation can be written as

F=\frac{m(v-u)}{\Delta t}

In this problem:

m = 5 kg is the mass of the fist

u = 9 m/s is the initial velocity

v = 0 is the final velocity

F = -45,000 N is the force applied (negative because its direction is opposite to the motion)

Therefore, we can re-arrange the equation to solve for the time:

\Delta t=\frac{m(v-u)}{F}=\frac{(5)(0-9)}{-45,000}=0.001 s

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Answer:

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