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3 years ago

The air pressure inside a submarine is 0.832atm. What would the pressure be in mnhg

Chemistry

1 answer:

Gwar [14]3 years ago

5 0

Answer:

632.32 mmHg

Explanation:

Millimetre mercury:

It is the monometric unit of pressure. It is define as "The pressure exerted by the column pf mercury at the height of 1 millimetre.

It is represented as mmHg.

It can also be written as mm Hg.

Atmosphere (atm):

It is barometric pressure, define as "The force exerted by atmospheric column on per unit area".

It is written as "atm".

Conversion of atm to mmHg:

0.832 atm × 760 mmHg / 1 atm

632.32 mmHg

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After balancing the equation, the reaction ratio between C2H2 and O2 is 2:5.

The moles of O2 in this reaction is 84.0 mol. According to the above ratio, the moles of C2H2 needed to react completely with the O2 is 84.0mole *2/5 = 33.6 mole.

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Choose the atom with:

nata0808 [166]

Answer:

a )Li

b)O

c)F

Explanation:

a) Li-1s^2 2s^1

F-1s^2 2s^2 2p^5

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3 years ago

When of alanine are dissolved in of a certain mystery liquid , the freezing point of the solution is less than the freezing poin

LenaWriter [7]

The question is incomplete, the complete question is:

When 177. g of alanine $(C_3H_7NO_2)$ are dissolved in 800.0 g of a certain mystery liquid X, the freezing point of the solution is $5.9^oC$ lower than the freezing point of pure X. On the other hand, when 177.0 g of potassium bromide are dissolved in the same mass of X, the freezing point of the solution is $7.2^oC$ lower than the freezing point of pure X. Calculate the van't Hoff factor for potassium bromide in X.

Answer: The van't Hoff factor for potassium bromide in X is 1.63

Explanation:

Depression in the freezing point is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution.

The expression for the calculation of depression in freezing point is:

$\Delta T_f=i\times K_f\times m$