All categories

3 years ago

The air pressure inside a submarine is 0.832atm. What would the pressure be in mnhg

Chemistry

1 answer:

Gwar [14]3 years ago

5 0

Answer:

632.32 mmHg

Explanation:

Millimetre mercury:

It is the monometric unit of pressure. It is define as "The pressure exerted by the column pf mercury at the height of 1 millimetre.

It is represented as mmHg.

It can also be written as mm Hg.

Atmosphere (atm):

It is barometric pressure, define as "The force exerted by atmospheric column on per unit area".

It is written as "atm".

Conversion of atm to mmHg:

0.832 atm × 760 mmHg / 1 atm

632.32 mmHg

You might be interested in

A buffer solution contains 0.496 M hydrocyanic acid and 0.399 M sodium cyanide . If 0.0461 moles of sodium hydroxide are added t

pochemuha

Answer : The pH of the solution is, 9.63

Explanation : Given,

The dissociation constant for HCN = $pK_a=9.31$

First we have to calculate the moles of HCN and NaCN.

$\text{Moles of HCN}=\text{Concentration of HCN}\times \text{Volume of solution}=0.496M\times 0.225L=0.1116mole$

and,

$\text{Moles of NaCN}=\text{Concentration of NaCN}\times \text{Volume of solution}=0.399M\times 0.225L=0.08978mole$

The balanced chemical reaction is:

$HCN+NaOH\rightarrow NaCN+H_2O$

Initial moles 0.1116 0.0461 0.08978

At eqm. (0.1116-0.0461) 0 (0.08978+0.0461)

0.0655 0.1359

Now we have to calculate the pH of the solution.

Using Henderson Hesselbach equation :

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

Now put all the given values in this expression, we get:

$pH=9.31+\log (\frac{0.1359}{0.0655})$

$pH=9.63$

Therefore, the pH of the solution is, 9.63

4 0

3 years ago

The reaction of perchloric acid (HClO4) with lithium hydroxide (LiOH) is described by the equation: HClO4 + LiOH → LiClO4 + H2O

dem82 [27]

Answer:

A. 0.35 M

Explanation:

Hello,

In this case, given the volume and concentration of lithium hydroxide and the volume of chloric acid, we can compute the concentration of the neutralized acid by using the following equation:

$n_{acid}=n_{base}\\\\V_{acid}M_{acid}=V_{base}M_{base}\\\\M_{acid}=\frac{V_{base}M_{base}}{V_{acid}} =\frac{46.9mL*0.75M}{100mL}\\ \\M_{acid}=0.35M$

Therefore, answer is A. 0.35 M.

Regards.

3 0

3 years ago

What is the energy change if 84.0 g of calcium oxide (CaO) reacts with excess water in the following reaction?

pochemuha

The energy change if 84.0 g of CaO react with excess water is 98KJ of heat is released.

calculation
heat = number of moles x delta H

delta H = - 65.2 Kj/mol

first find the number of moles of CaO reacted

moles = mass/molar mass
the molar mass of CaO = 40 + 16= 56 g/mol
mass = 84 g
moles therefore = 84 g/56 g/mol =1.5 moles

Heat is therefore = 1.5 moles x -65.2 = - 97.8 Kj = -98 Kj

since sign is negative the energy is released

6 0

3 years ago

The nuclear fission process releases neutrons and

yuradex [85]

<span>the answer is c. energy</span>

3 0

3 years ago

A florist prepares a solution of nitrogen-phosphorus fertilizer by dissolving 5.66 g of NH₄NO₃ and 4.42 g of (NH₄)₃ PO₄ in enoug

Alexandra [31]

In finding the molarity of a solution, we use the following formula:

$M=moles soluteL solution$