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Firdavs [7]
9 months ago
9

in case one, a car speeds up from zero m/s to 15 m/s. in case two, the same car speeds up from 15 m/s to 30 m/s. the mass of the

car is 1000 kg. compare the energy needed to provide the increase in speed in each case. give your answers in joules. (a) in case one, how much energy is needed? j (b) in case two, how much energy is needed? j (c) in case two, how many more times the energy was needed than in case one? three times as much energy was needed. four times as much energy was needed. the same amount of energy was needed in both cases. twice as much energy was needed.
Physics
1 answer:
GrogVix [38]9 months ago
7 0

Three time  the energy was needed than in case one.

What is energy?

In physics, energy is the quantifiable property that is transmitted to a body or a physical system and is visible in the form of heat and light. The law of conservation of energy states that energy can be converted in form but cannot be created or destroyed.

Case 1:

Vo = 0 m/s

V1 = 15 m/s

Case 2:

Vo = 15 m/s

V1 = 30 m/s

Change in KE = 1/2 × m × (V1^2 - Vo^2)

KE1 = 1/2 × 1000 × (15^2 - 0)

= 112.5 kJ

KE2 = 1/2 × 1000 × (30^2 - 15^2)

= 1/2 × 1000 × 675

= 337.5kJ

Case 1 has an increase of 112.5 kJ energy while Case 2 has an increase of 337.5kJ.

To know more about energy click

brainly.com/question/582060

#SPJ4

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The work-energy theorem explains the idea that the net work - the total work done by all the forces combined - done on an object is equal to the change in the kinetic energy of the object. After the net force is removed (no more work is being done) the object's total energy is altered as a result of the work that was done.

This idea is expressed in the following equation:

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2 years ago
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An RC circuit is connected across an ideal DC voltage source through an open switch. The switch is closed at time t = 0 s. Which
steposvetlana [31]

Answer:

e)

Explanation:

In an RC series circuit, at any time, the sum of the voltages through the resistor and the capacitor must be constant and equal to the voltage of the DC voltage source, in order to be compliant with KVL.

At= 0, as the voltage through the capacitor can't change instantaneously, all the voltage appears through the resistor, which means that a current flows, that begins to charge the capacitor, up to a point that the voltage through the capacitor is exactly equal to the DC voltage, so no current flows in the circuit anymore, and the charge in the capacitor reaches to its maximum value.

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2 years ago
Is (kr) an element a compound or a mixture?
Xelga [282]

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A small block on a frictionless, horizontal surface has a mass of 0.0250 kg. It is attached to a massless cord passing through a
frosja888 [35]

Answer:

a) Yes

b) 7 rad/s

c) 0.01034 J

Explanation:

a)

Yes the angular momentum of the block is conserved since the net torque on the block is zero.

b)

m = mass of the block = 0.0250 kg

w₀ = initial angular speed before puling the cord = 1.75 rad/s

r₀ = initial radius before puling the cord = 0.3 m

w = final angular speed after puling the cord = ?

r = final  radius after puling the cord = 0.15 m

Using conservation of angular momentum

m r₀² w₀ = m r² w

r₀² w₀ = r² w

(0.3)² (1.75) = (0.15)² w

w = 7 rad/s

c)

Change in kinetic energy is given as

ΔKE = (0.5) (m r² w² - m r₀² w₀²)

ΔKE = (0.5) ((0.025) (0.15)² (7)² - (0.025) (0.3)² (1.75)²)

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