All categories

3 years ago

Which of the following

Mathematics

1 answer:

Ronch [10]3 years ago

3 0

Answer:

Option A

Step-by-step explanation:

Given equation is

=> 3y = 6x + 3

In slope-intercept form, it becomes

=> 3y = 3(2x+1)

=> y = 2x+1

So, Slope = m = 2

Parallel lines have equal slope, So any line parallel to the above line would have its slope equal to 2

=> Line parallel to 3y = 6x + 3 is y = 2x + 10

You might be interested in

please help me with this IXL i only have an hour like i said on my last question and please tell me how to get the answer so i c

damaskus [11]

It is y=2x-6. Anymore questions?

3 0

3 years ago

Read 2 more answers

Kate wants to have $25,000 in 16 years. How much does she need to invest if the interest rate is 6 percent per year?

Diano4ka-milaya [45]

I'm guessing that its c

6 0

3 years ago

Read 2 more answers

3x + y = 14 y = 5 Solve the system of equations

lorasvet [3.4K]

Answer:

X=3, y=5

Step-by-step explanation:

3x + y = 14 equation 1

y=5 equation 2

3x + 5 = 14. substitute value of y from equation 2 into equation 1

3x=9

x-3

6 0

3 years ago

Is (6,1)(8,-3)(6,7) a function

pochemuha

Answer:

No It's not

Step-by-step explanation:

Since

x=6 produces y=1 and y=7, the relation (6,1),(8,−3),(6,7) is not a function.

The relation is not a function.

6 0

3 years ago

Read 2 more answers

The time it takes for a planet to complete its orbit around a particular star is called the? planet's sidereal year. The siderea

BartSMP [9]

Answer:

(a) See below

(b) r = 0.9879

(d) See below

(e) No.

Step-by-step explanation:

(a) Plot the data

I used Excel to plot your data and got the graph in Fig 1 below.

(b) Correlation coefficient

One formula for the correlation coefficient is

$r = \dfrac{\sum{xy} - \sum{x} \sum{y}}{\sqrt{\left [n\sum{x}^{2}-\left (\sum{x}\right )^{2}\right]\left [n\sum{y}^{2} -\left (\sum{y}\right )^{2}\right]}}$

The calculation is not difficult, but it is tedious.

(i) Calculate the intermediate numbers

We can display them in a table.

x y xy x² y²

36 0.22 7.92 1296 0.05

67 0.62 42.21 4489 0.40

93 1.00 93.00 20164 3.46

433 11.8 5699.4 233289 139.24

887 29.3 25989.1 786769 858.49

1785 82.0 146370 3186225 6724

2797 163.0 455911 7823209 26569

3675 248.0 911400 13505625 61504

9965 537.81 1545776.75 25569715 95799.63

(ii) Calculate the correlation coefficient

$r = \dfrac{\sum{xy} - \sum{x} \sum{y}}{\sqrt{\left [n\sum{x}^{2}-\left (\sum{x}\right )^{2}\right]\left [n\sum{y}^{2} -\left (\sum{y}\right )^{2}\right]}}\\\\= \dfrac{9\times 1545776.75 - 9965\times 537.81}{\sqrt{[9\times 25569715 -9965^{2}][9\times 95799.63 - 537.81^{2}]}} \approx \mathbf{0.9879}$

(c) Regression line

The equation for the regression line is

y = a + bx where

$a = \dfrac{\sum y \sum x^{2} - \sum x \sum xy}{n\sum x^{2}- \left (\sum x\right )^{2}}\\\\= \dfrac{537.81\times 25569715 - 9965 \times 1545776.75}{9\times 25569715 - 9965^{2}} \approx \mathbf{-12.629}\\\\b = \dfrac{n \sum xy - \sum x \sum y}{n\sum x^{2}- \left (\sum x\right )^{2}} - \dfrac{9\times 1545776.75 - 9965 \times 537.81}{9\times 25569715 - 9965^{2}} \approx\mathbf{0.0654}\\\\\\\text{The equation for the regression line is $\large \boxed{\mathbf{y = -12.629 + 0.0654x}}$}$

(d) Residuals

Insert the values of x into the regression equation to get the estimated values of y.

Then take the difference between the actual and estimated values to get the residuals.

x y Estimated Residual

36 0.22 -10 10

67 0.62 -8 9

93 1.00 -7 8

142 1.86 -3 5

433 11.8 19 - 7

887 29.3 45 -16

1785 82.0 104 -22

2797 163.0 170 - 7

3675 248.0 228 20

(e) Suitability of regression line

A linear model would have the residuals scattered randomly above and below a horizontal line.

Instead, they appear to lie along a parabola (Fig. 2).

This suggests that linear regression is not a good model for the data.

4 0

3 years ago