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pochemuha
1 year ago
12

very fine smoke particles are suspended in air. the translational rms speed of a smoke particle is 2.45 10-3 m/s, and the temper

ature is 288 k. find the mass of a particle?
Physics
1 answer:
m_a_m_a [10]1 year ago
5 0

The mass of a particle is 2.2x10⁻¹⁵ kg

Consider smoke particles as an ideal gas

The translational RMS speed of the smoke particles is 2.45x10⁻³ m/s.

<em>v= √3kT/m</em>

<em>where k= 1.38x10⁻²³J/K, T is 288K, and m is the mass of the smoke particle</em>

<em>2.45x10⁻³ = √3x1.38x10⁻²³x288/m</em>

<em>m= 2.2x10⁻¹⁵ kg</em>

Therefore, the mass of a particle is 2.2x10⁻¹⁵ kg.

To learn more about the translational root mean square speed of gases, visit brainly.com/question/6853705

#SPJ4

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The charged rod is held above the balloon and the weight of the balloon acts in downwards direction. To balance the weight of the balloon, the force on the balloon due to the rod must be directed along the upwards direction, which is only possible when the rod exerts an attractive force on the balloon and the electrostatic force on the balloon due to the rod is attractive when the polarities of the charge on the two are different.

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In order to balloon to be float in air, the weight of the balloom must be balanced with the electrostatic force on the balloon due to rod.

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\rm F_e = W\\\dfrac{1}{4\pi \epsilon_o}\dfrac{|q_1||q_2|}{d^2}=W\\8.99\times 10^9\times \dfrac{3.50\times10^{-8}\times |q_2| }{0.0640^2}=2.70\times 10^{-2}\\|q_2| = \dfrac{2.70\times 10^{-2}\times 0.00640^2}{8.99\times 10^9\times 2.70\times 10^{-7}}=4.56\times 10^{-10}\ C.

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