The momentum p of a moving particle is the product between its mass, m, and tis velocity, v:
![p=mv](https://tex.z-dn.net/?f=p%3Dmv)
In our problem, we know
![p=10^{-16}~Kg \cdot m/s](https://tex.z-dn.net/?f=p%3D10%5E%7B-16%7D~Kg%20%5Ccdot%20m%2Fs)
and
![v=0.87c=0.87\cdot 3\cdot10^8~m/s=2.61\cdot 10^8~m/s](https://tex.z-dn.net/?f=v%3D0.87c%3D0.87%5Ccdot%203%5Ccdot10%5E8~m%2Fs%3D2.61%5Ccdot%2010%5E8~m%2Fs)
, and using the relationship mentioned above, we can find the mass m of the particle:
Correct choices are marked in bold:
travel in straight lines and can bounce off surfaces --> TRUE, normally electromagnetic waves travel in straight lines, however they can be reflected by objects, bouncing off their surfaces
travel through space at the speed of light --> TRUE, all electromagnetic waves in space (vacuum) travel at the speed of light,
)
travel only through matter --> FALSE; electromagnetic waves can also travel through vacuum
travel only through space --> FALSE, electromagnetic waves can also travel through matter
can bend around objects --> TRUE, this is what happens for instance when diffraction occurs: electromagnetic waves are bended around obstacles or small slits
move by particles bumping into each other --> FALSE, electromagnetic waves are oscillations of electric and magnetic fields, so no particles are involved
move by the interaction between an electric field and a magnetic field --> TRUE, electromagnetic waves consist of an electric field and a magnetic field oscillating in a direction perpendicular to the direction of motion of the wave
Answer:
The frequency increases by a factor of 3.
Explanation:
The relation between speed, wavelength and frequency of a wave is given by :
![v=f\lambda](https://tex.z-dn.net/?f=v%3Df%5Clambda)
or
![f\propto \dfrac{1}{\lambda}](https://tex.z-dn.net/?f=f%5Cpropto%20%5Cdfrac%7B1%7D%7B%5Clambda%7D)
A wave travels at a constant speed. If the wavelength is reduced by a factor of 3, it would mean that the frequency increases by a factor of 3 because there is an inverse relationship between wavelength and frequency.
Answer: 576.48 N*m^2/C
Explanation: In order to calculate the electric flux through the any surface we have to take into account the scalar product between the electric field vector and the normal vector to the surface.
So we have:
ФE= E*A= 1.33 * 10^4*0.0518* cos (33.2°)= 576.48 N*m^2/C