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mezya [45]
2 years ago
9

True or false your vocal cords act like a guitar string when it comes to sound

Physics
2 answers:
torisob [31]2 years ago
8 0

Answer:

True

Explanation:

inna [77]2 years ago
3 0
The answer to this question is true
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3 years ago
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A nail is hit with a hammer. Which type of contact force has been applied?
kotegsom [21]
D or b you chose because it can go any way
8 0
3 years ago
What is the moment of inertia of an object that rolls without slipping down a 2.00-m-high incline starting from rest, and has a
Paha777 [63]
E = mgh +  \frac{1}2} m v^{2} + \frac{1}{2} I \omega^{2} = mgh +  \frac{1}2} m  r ^{2}   \omega ^{2}  + \frac{1}{2} I \omega^{2}

for a solid cylinder:  I =  \frac{1}{2} m r^{2}
for a hollow cylinder: I = mr^{2}

I will look at the case of a hollow cylinder:

E = mgh + I \omega ^{2} = constant \\ \\ I =  \frac{mgh}{  \omega^{2} }

That is as far as i get.


7 0
3 years ago
A block slides down a frictionless inclined ramp. If the ramp angle is 17.0° and its length is find the speed of the block as it
SashulF [63]

Answer:

2.4\sqrt{L} where L is the length of the ramp

Explanation:

Let L (m) be the length of the ramp, and g = 9.81 m/s2 be the gravitational acceleration acting downward. This g vector can be split into 2 components: parallel and perpendicular to the ramp.

The parallel component would have a magnitude of

gsin\theta = 9.81 sin17^o = 2.87 m/s^2

We can use the following equation of motion to find out the final velocity of the book after sliding L m:

v^2 - v_0^2 = 2a\Delta s

where v m/s is the final velocity, v_0 = 0m/s is the initial velocity when it starts from rest, a = 2.87 m/s2 is the acceleration, and \Delta s = L is the distance traveled:

v^2 - 0 = 2*2.87*L

v = \sqrt{5.74L} = 2.4\sqrt{L}

6 0
3 years ago
A piano tuner stretches a steel piano wire with a tension of 800 N. The steel wire is 0.400 m long and has a mass of 3.00 g. Wha
stepan [7]

Answer:

408.25 Hz.

Explanation:

The fundamental frequency of a stretched string is given as

f' = 1/2L√(T/m') .................... Equation 1

Note: The a steel piano wire is a string

Where f' = fundamental frequency of the wire, L = length of the wire, T = tension on the wire, m' = mass per unit length of the wire.

Given: L = 0.4 m, T = 800 N,

Also,

m' = m/L where m = mass of the steel wire = 3.00 g = 3/1000 = 0.003 kg.

L = 0.4 m

m' = 0.003/0.4 = 0.0075 kg/m.

Substituting into equation 1

f' = 1/(2×0.4)[√(800/0.0075)]

f' = 1/0.8[√(106666.67)]

f' = 326.599/0.8

f' = 408.25 Hz.

Hence the frequency of the fundamental mode of vibration = 408.25 Hz.

8 0
3 years ago
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