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lyudmila [28]
3 years ago
5

Best Answer gets Brainiest

Physics
1 answer:
Alexeev081 [22]3 years ago
6 0

Answer:

yoo yoo

24

Explanation:

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Sergei uses a lever to lift a heavy rock. He obtains a 2.5m lever and places the fulcrum 0.7m from the rock. What is the ideal m
Anit [1.1K]

Answer:

m = 3.57

Explanation:

Given that,

Sergei uses a lever to lift a heavy rock. He obtains a 2.5m lever and places the fulcrum 0.7m from the rock.

We need to find the ideal mechanical advantage of Sergei's lever.

It is equal to the ratio of resistance arm to the effort arm. In terms of length it is given by :

m=\dfrac{d_2}{d_1}\\\\m=\dfrac{2.5}{0.7}\\\\=3.57

So, the ideal mechanical advantage of the lever is 3.57.

4 0
3 years ago
A 50 kg boy is at the edge of a circular platform of radius 4.0 m which is rotating freely
Flauer [41]

Answer:

0.62 rad/s

Explanation:

Angular momentum is conserved.

I₁ ω₁ = I₂ ω₂

where I is moment of inertia and ω is angular velocity.

The total moment of inertia is the sum of the platform's inertia and the boy's.

(I + m r₁²) ω₁ = (I + m r₂²) ω₂

Given I = 1000 kg m², m = 50 kg, r₁ = 4.0 m, r₂ = 3.0 m, and ω₁ = 0.5 rad/s:

(1000 + 50 (4.0)²) (0.5) = (1000 + 50 (3.0)²) ω₂

900 = 1450 ω₂

ω₂ = 0.62 rad/s

8 0
4 years ago
Which one of the statements below is true about mechanical waves?
balandron [24]

Answer:D

Explanation:

7 0
3 years ago
A 2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 V?
SpyIntel [72]

Answer:

U= 0.112 x10^{-6} J

u= 0.708 \frac{J}{m^{3} }

Explanation:

diameter= 2 cm

r= 1 cm * \frac{1m}{100cm} = 0.01 m

distance= 0.5 mm

d= 0.5 mm * \frac{1m}{1000m}= 0.5 x10^{-3}

Area A= \pi *r^{2}= 0.314x10^{-3}  m^{2}

Volume v= A*d = 0.314 x10^{-3}m^{2}*0.5x10^{-3} m =0.157x10^{-6}  m^{3}

v= 0.157 x10^{-6} m^{3}

Constant vacuum permittivity

E_{o}= 8.85x10^{-12}

a).

C= \frac{A*E_{o} }{d} = \frac{0.314x10^{-3} *8.85x10^{-12}  }{0.5x10^{-3} } \\C= 5.56 x10^{-12}F

U= \frac{1}{2} *C *V^{2}\\ U=\frac{1}{2} * 5.56x10^{-12}*(200)^{2}  \\U=0.112 x^{-6} J\\

b).

u=\frac{U}{v}

u=\frac{0.112 x10^{-6}J}{0.157x10^{-6}m^{3}  } \\u=0.708 \frac{J}{m^{3} }

5 0
4 years ago
What color will the paper appear? Explain why?
Evgen [1.6K]

Answer:

The answer is B

Explanation:

6 0
3 years ago
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