<h2>The gravitational potential energy is double for stone with twice the mass of other stone.</h2>
Explanation:
Let mass of stone 1 be m.
Mass of stone 2 is twice the mass of stone 1.
Mass of stone 2 = 2m
We know that
Gravitational potential energy = Mass x acceleration due to gravity x Height
PE = mgh
For stone 1 ,
PE₁ = mgh
For stone 2 ,
PE₂ = 2mgh = 2 PE₁
So the gravitational potential energy is double for stone with twice the mass of other stone.
I think the correct answer from the choices listed above is option C. Lithospheric plates move constantly due to the density differences. Lithospheric plates<span> are another name for tectonic plates, which are part of the Earth's uppermost layer, the crust.</span>
Answer:
The source is at a distance of 4.56 m from the first point.
Solution:
As per the question:
Separation distance between the points, d = 11.0 m
Sound level at the first point, L = 66.40 dB
Sound level at the second point, L'= 55.74 dB
Now,
where
I = Intensity of sound
Now,
Similarly,
Now,
Solving the above quadratic eqn, we get:
R = 4.56 m
Answer:
The size of the force developing inside the steel rod is 32039.28 N
Explanation:
Given;
length of the steel rod, L = 1.55 m
cross sectional area of the steel, A = 4.89 cm²
temperature change, ∆T = 28.0 K
coefficient of linear expansion for steel, α = 1.17 × 10⁻⁵ 1/K
Young modulus of steel, E = 200.0 GPa.
Extension of the steel is given as;
α ∆T L = FL / AE
α ∆T = F/AE
F = AEα ∆T
F = ( 4.89 x 10⁻⁴)(200 x 10⁹)(1.17 × 10⁻⁵)(28.0 K)
F = 32039.28 N
Therefore, the size of the force developing inside the steel rod when its temperature is raised, is 32039.28 N
