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Len [333]
1 year ago
7

The two concepts or issues that you chose and explain how each either has contributed to or detracted from social change, specif

ically in the form of racial and ethnic equality.
Physics
1 answer:
Rom4ik [11]1 year ago
3 0

Racial equality directed to a scenario in which individuals of all races and ethnicities exists treated equally, regardless of any differences in physical characteristics.

<h3>What is meant by racial equality? </h3>

Racial equality occurs when organizations, like schools, give people of all races equal chances regardless of their physical characteristics, such skin color. It has always been difficult for ethnic minorities to achieve equality, especially in educational institutions.

According to research, black pupils face fewer expectations from their teachers and are more likely to be suspended or expelled than white students. They are also less likely to be enrolled in gifted programs.

The term "racial equality" describes a situation in which people of all races and ethnicities are treated equally, regardless of any physical distinctions. Racial equality occurs when institutions uphold people's moral, legal, and political rights.

To learn more about Racial equality refer to:

brainly.com/question/12645755

#SPJ9

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Examine the reactants of the incomplete double displacement reaction.
Bumek [7]
<h3>Answer:</h3>

AgCl + NaNO₃

<h3>Explanation:</h3>
  • The reaction between silver nitrate and sodium chloride is an example of a double displacement reaction.
  • In a double displacement reaction compounds or salts reacts and exchange cations or anions to form new compounds or salts.
  • In this case, silver nitrate and sodium chloride exchange anions and cations to form silver chloride and sodium nitrate.
  • Therefore, the complete reaction is given by;

AgNO3 + NaCl → AgCl + NaNO₃

  • But since silver chloride is a precipitate, the reaction may also be an example of a precipitation reaction.
8 0
3 years ago
An airplane of mass 1.60 ✕ 104 kg is moving at 66.0 m/s. The pilot then increases the engine's thrust to 7.70 ✕ 104 N. The resis
Ivan

(a) No, because the mechanical energy is not conserved

Explanation:

The work-energy theorem states that the work done by the engine on the airplane is equal to the gain in kinetic energy of the plane:

W=\Delta K (1)

However, this theorem is only valid if there are no non-conservative forces acting on the plane. However, in this case there is air resistance acting on the plane: this means that the work-energy theorem is no longer valid, because the mechanical energy is not conserved.

Therefore, eq. (1) can be rewritten as

W=\Delta K + E_{lost}

which means that the work done by the engine (W) is used partially to increase the kinetic energy of the airplane (\Delta K) and part is lost because of the air resistance (E_{lost}).

(b) 77.8 m/s

First of all, we need to calculate the net force acting on the plane, which is equal to the difference between the thrust force and the air resistance:

F=7.70\cdot 10^4 N - 5.00 \cdot 10^4 N=2.70\cdot 10^4 N

Now we can calculate the acceleration of the plane, by using Newton's second law:

a=\frac{F}{m}=\frac{2.70\cdot 10^4 N}{1.60\cdot 10^4 kg}=1.69 m/s^2

where m is the mass of the plane.

Finally, we can calculate the final speed of the plane by using the equation:

v^2- u^2 = 2aS

where

v=? is the final velocity

u=66.0 m/s is the initial velocity

a=1.69 m/s^2 is the acceleration

S=5.00 \cdot 10^2 m is the distance travelled

Solving for v, we find

v=\sqrt{u^2+2aS}=\sqrt{(66.0 m/s)^2+2(1.69 m/s^2)(5.00\cdot 10^2 m)}=77.8 m/s

8 0
3 years ago
The longest passenger liner ever built was the France, 66,348 tons and 315.5 long. Suppose its front end passes the edge of a pi
Kaylis [27]

Answer:

The back end of the vessel will pass the pier at 4.83 m/s

Explanation:

This is purely a kinetics question (assuming we're ignoring drag and other forces) so the weight of the boat doesn't matter. We're given:

Δd = 315.5 m

vi = 2.10 m/s

a = 0.03 m/s^2

vf = ?

The kinetics equation that incorporates all these variables is:

vf^2 = vi^2 + 2aΔd

vf = √(2.1^2 + 2(0.03)(315.5))

vf = 4.83 m/s

5 0
3 years ago
A rigid tank initially contains 3kg of carbon dioxide (CO2) at a pressure of 3bar.The tank is connected by a valve to a friction
marissa [1.9K]

Answer:

Part a: <em>The total amount of energy transfer by the work done is 54.81 kJ.</em>

Part b: <em>The total amount of energy transfer by the heat is 54.81 kJ</em>

Explanation:

Mass of Carbon Dioxide is given as m1=3 kg

Pressure is given as P1=3 bar =300 kPA

Volume is given as V1=0.5 m^3

Pressure in tank 2 is given as P2=2 bar=200 kPa

T=290 K

Now the Molecular weight of CO_2 is given as

M=44 kg/kmol

the gas constant is given as

R=\frac{\bar{R}}{M}\\R=\frac{8.314}{44}\\R=0.189 kJ/kg.K

Volume of the tank is given as

V=\frac{mRT}{P_1}\\V=\frac{3 \times 0.189 \times 290}{300 }\\V=0.5481 m^3

Final mass is given as

m_2=\frac{P_2V}{RT}\\m_2=\frac{200\times 0.5481}{0.189\times 290}\\m_2=2 kg

Mass of the CO2 moved to the cylinder

m=m_1-m_3\\m=3-2=1 kg

The initial mass in the cylinder is given as

m_{(cyl)_1}=\frac{P_{(cyl)_1}V_1}{RT}\\m_{(cyl)_1}=\frac{200\times 0.5}{0.189 \times 290}\\m_{(cyl)_1}=1.82 kg

The mass after the process is

m_{(cyl)_2}=m_{(cyl)_1}+m\\m_{(cyl)_2}=1.82+1\\m_{(cyl)_2}=2.82\\

Now the volume 2 of the cylinder is given as

V_{(cyl)_2}=\frac{m_{(cyl)_2}RT}{P_2}\\m_{(cyl)_2}=\frac{2.82\times 0.189\times 290}{200}\\m_{(cyl)_1}=0.774 m^3

Part a:

So the Work done is given as

W=P(V_2-V_1)\\W=200(0.774-0.5)\\W=54.81 kJ

<em>The total amount of energy transfer by the work done is 54.81 kJ.</em>

Part b:

The total energy transfer by heat is given as

Q=\Delta U+W\\Q=0+W\\Q=54.81 kJ

As the temperature is constant thus change in internal energy is 0.

<em>The total amount of energy transfer by the heat is 54.81 kJ</em>

7 0
3 years ago
Which of the following best describes the location of the
marshall27 [118]

Answer:

The mantle exists above the crust of the earth

8 0
3 years ago
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