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Sauron [17]
3 years ago
5

If the magnitude of the magnetic force on a proton is F when it is moving at 18.0 ∘ with respect to the field, what is the magni

tude of the force (in terms of F) when this charge is moving at 33.0 ∘ with respect to the field?
Physics
1 answer:
Lelu [443]3 years ago
5 0

Answer:

The force when θ = 33° is 1.7625 times of the force when θ = 18°

Explanation:

The force on a moving charge through a magnetic field is given by

F = qvB sin θ

q = charge of the moving particle

v = Velocity of the moving charge

B = Magnetic field strength

θ = angle between the magnetic field and the velocity (direction of the motion) of the moving charge

Because qvB are all constant, we can call the expression K.

F = K sinθ

when θ = 18°,

F = K sin 18° = 0.309K

when θ = 33°, let the force be F₁

F₁ = K sin 33° = 0.5446K

(F₁/F) = (0.5446K/0.309K) = 1.7625

F₁ = 1.7625 F

Hope this Helps!!!

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The equation we can use here is:

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You perform the Hooke's Law experiment and create a plot of Displacement vs. Force. You add a linear fit and find the following
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3 years ago
A friend throws a heavy ball toward you while you are standing on smooth ice. You can either catch the ball or deflect it back t
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Answer:

Explanation:

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change in momentum in the ball will be maximum when the ball bounces back with the same velocity which can be shown as follows

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The fictional rocket ship Adventure is measured to be 50 m long by the ship's captain inside the rocket.When the rocket moves pa
tensa zangetsu [6.8K]

Complete question:

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Answer

a)Who would have aged less=The Captain would have aged less

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Explanation:

From the question we are told that

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a)

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