Answer:
Sn2 mechanism reaction
Explanation:
In this case, we have a <u>primary substrate</u> (1-bromo-3,3-dimethylbutane). Because the <u>leaving grou</u>p "Br" is bonded to a <u>primary carbon</u>. Additionally, the nucleophile will come from the "NaI" (sodium iodide). This is an <u>ionic compound</u>, so, in solution, a cation and an anion would be produced. The anion
would be the <u>nucleophile</u>.
Due to the primary substrate, we will have an <u>Sn2 reaction</u>. So, the attack of the nucleophile and the removal of the leaving group will take place in <u>1 step</u>. Producing a <u>"transition state"</u> and finally and the final product (1-iodo-3,3-dimethylbutane).
See figure 1
I hope it helps!
1 g/cm³ --------------- 0.1 kg/dL
7.86 g/cm³ ---------- ?
7.86 x 0.1 / 1 => 0.786 kg/dL
D = m / V
0.786 = 3.56 / V
V = 3.56 / 0.786
V = 4.529 dL
<span>hope this helps!</span>
Answer:
chalk bubbles with vinegar
1 ba+2 br——>1 babr2
u just have to make sure u have the same number of each type of atom on either side of the equation:)