A boy eat a energy of a sandwich to run a race because when they eat a sandwich it helps them to help it mid workout and real nutritions of NYC and bring extra fuel and eating the right thing
I hope this help
Answer:
Activation energy for creep in this temperature range is Q = 252.2 kJ/mol
Explanation:
To calculate the creep rate at a particular temperature
creep rate, ![\zeta_{\theta} = C \exp(\frac{-Q}{R \theta} )](https://tex.z-dn.net/?f=%5Czeta_%7B%5Ctheta%7D%20%3D%20C%20%5Cexp%28%5Cfrac%7B-Q%7D%7BR%20%5Ctheta%7D%20%29)
Creep rate at 800⁰C, ![\zeta_{800} = C \exp(\frac{-Q}{R (800+273)} )](https://tex.z-dn.net/?f=%5Czeta_%7B800%7D%20%3D%20C%20%5Cexp%28%5Cfrac%7B-Q%7D%7BR%20%28800%2B273%29%7D%20%29)
![\zeta_{800} = C \exp(\frac{-Q}{1073R} )\\\zeta_{800} = 1 \% per hour =0.01\\](https://tex.z-dn.net/?f=%5Czeta_%7B800%7D%20%3D%20C%20%5Cexp%28%5Cfrac%7B-Q%7D%7B1073R%7D%20%29%5C%5C%5Czeta_%7B800%7D%20%3D%201%20%5C%25%20per%20hour%20%3D0.01%5C%5C)
.........................(1)
Creep rate at 700⁰C
![\zeta_{700} = C \exp(\frac{-Q}{R (700+273)} )](https://tex.z-dn.net/?f=%5Czeta_%7B700%7D%20%3D%20C%20%5Cexp%28%5Cfrac%7B-Q%7D%7BR%20%28700%2B273%29%7D%20%29)
![\zeta_{800} = C \exp(\frac{-Q}{973R} )\\\zeta_{800} = 5.5 * 10^{-2} \% per hour =5.5 * 10^{-4}](https://tex.z-dn.net/?f=%5Czeta_%7B800%7D%20%3D%20C%20%5Cexp%28%5Cfrac%7B-Q%7D%7B973R%7D%20%29%5C%5C%5Czeta_%7B800%7D%20%3D%205.5%20%2A%2010%5E%7B-2%7D%20%20%5C%25%20per%20hour%20%3D5.5%20%2A%2010%5E%7B-4%7D)
.................(2)
Divide equation (1) by equation (2)
![\frac{0.01}{5.5 * 10^{-4} } = \exp[\frac{-Q}{1073R} -\frac{-Q}{973R} ]\\18.182= \exp[\frac{-Q}{1073R} +\frac{Q}{973R} ]\\R = 8.314\\18.182= \exp[\frac{-Q}{1073*8.314} +\frac{Q}{973*8.314} ]\\18.182= \exp[0.0000115 Q]\\](https://tex.z-dn.net/?f=%5Cfrac%7B0.01%7D%7B5.5%20%2A%2010%5E%7B-4%7D%20%7D%20%3D%20%5Cexp%5B%5Cfrac%7B-Q%7D%7B1073R%7D%20-%5Cfrac%7B-Q%7D%7B973R%7D%20%5D%5C%5C18.182%3D%20%5Cexp%5B%5Cfrac%7B-Q%7D%7B1073R%7D%20%2B%5Cfrac%7BQ%7D%7B973R%7D%20%5D%5C%5CR%20%3D%208.314%5C%5C18.182%3D%20%5Cexp%5B%5Cfrac%7B-Q%7D%7B1073%2A8.314%7D%20%2B%5Cfrac%7BQ%7D%7B973%2A8.314%7D%20%5D%5C%5C18.182%3D%20%5Cexp%5B0.0000115%20Q%5D%5C%5C)
Take the natural log of both sides
![ln 18.182= 0.0000115Q\\2.9004 = 0.0000115Q\\Q = 2.9004/0.0000115\\Q = 252211.49 J/mol\\Q = 252.2 kJ/mol](https://tex.z-dn.net/?f=ln%2018.182%3D%200.0000115Q%5C%5C2.9004%20%3D%200.0000115Q%5C%5CQ%20%3D%202.9004%2F0.0000115%5C%5CQ%20%3D%20252211.49%20J%2Fmol%5C%5CQ%20%3D%20252.2%20kJ%2Fmol)
Answer:
See explaination
Explanation:
Let's define tuple as an immutable list of Python objects which means it can not be changed in any way once it has been created.
Take a look at the attached file for a further detailed and step by step solution of the given problem.
Answer:
true
Explanation:
Creep is known as the time dependent deformation of structure due to constant load acting on the body.
Creep is generally seen at high temperature.
Due to creep the length of the structure increases which is not fit for serviceability purpose.
When time passes structure gain strength as the structure strength increases with time so creep tends to decrease.
When we talk about Creep rate for new structure the creep will be more than the old structure i.e. the creep rate decreases with time.
Answer:
hello your question lacks some information attached below is the complete question with the required information
answer : 81.63 mm
Explanation:
settlement of the surface due to compression of the clay ( new consolidated )
= 81.63 mm
attached below is a detailed solution to the given problem