Answer:
no not really
Explanation:
From your friendly neighborhood cereal killer,
Sir. BLOODPR1NCE
Answer:
C
Explanation:
N = Na.P/A------(1)
Na = avogadro's number = 6.02210²³
P = density
A = atomic weight of metal
When we substitute into equation 1 above we get
1.0x10²⁹atoms/m³
From here we calculate the number of vacancies
T = 1000⁰c = 1273K
The formula to use is
Nv= Nexo(Qt/K.T) -----(2)
Qt = 1.22eV
K = Boltzmann's constant = 8.6210x10^-5
When we substitute values into equation 2
We get Nv = 1.49 x 10²⁴m-3
Therefore option c is correct
Check attachment for a more detailed calculation of this question
Answer:
See explanations
Explanation:
Consider the following Venn diagram to retrieve the name of course that student Altvater took during semester I-2015.
• In above Venn diagram inner Ellipse represent the subquery part, this subquery part select the Student ID from STUDENT table.
• Second sub query is used to determine the SectionNo of all student whose studentID retrived in the first subquery
• Finally the main query displays the CourseName from COURSE table.
Answer:
Explanation:
Total weight being moved = 5000+1000+200
= 6200 lb .
Force applied = 700 lb
= 700 x 32 = 22400 poundal .
acceleration (a) = 22400 / 6200
= 3.613 ft /s²
To know velocity after 6 ft we apply the formula
v² = u² + 2as
v² = 0 + 2 x 3.613 x 6
43.356
v = 6.58 ft/s
Answer:
the pressure reading when connected a pressure gauge is 543.44 kPa
Explanation:
Given data
tank volume (V) = 400 L i.e 0.4 m³
temperature (T) = 25°C i.e. 25°C + 273 = 298 K
air mass (m) = 3 kg
atmospheric pressure = 98 kPa
To find out
pressure reading
Solution
we have find out pressure reading by gauge pressure
i.e. gauge pressure = absolute pressure - atmospheric pressure
first we find absolute pressure (p) by the ideal gas condition
i.e pV = mRT
p = mRT / V
p = ( 3 × 0.287 × 298 ) / 0.4
p = 641.44 kPa
so
gauge pressure = absolute pressure - atmospheric pressure
gauge pressure = 641.44 - 98
gauge pressure = 543.44 kPa