Answer:
γ
=0.01, P=248 kN
Explanation:
Given Data:
displacement = 2mm ;
height = 200mm ;
l = 400mm ;
w = 100 ;
G = 620 MPa = 620 N//mm²; 1MPa = 1N//mm²
a. Average Shear Strain:
The average shear strain can be determined by dividing the total displacement of plate by height
γ
= displacement / total height
= 2/200 = 0.01
b. Force P on upper plate:
Now, as we know that force per unit area equals to stress
τ = P/A
Also, τ = Gγ
By comapring both equations, we get
P/A = Gγ
------------ eq(1)
First we need to calculate total area,
A = l*w = 400 * 100= 4*10^4mm²
By putting the values in equation 1, we get
P/40000 = 620 * 0.01
P = 248000 N or 2.48 *10^5 N or 248 kN
Answer:
7.15
Explanation:
Firstly, the COP of such heat pump must be measured that is,

Therefore, the temperature relationship, 
Then, we should apply the values in the COP.


The number of heat rejected by the heat pump must then be calculated.


We must then calculate the refrigerant mass flow rate.



The
value is 145.27 and therefore the hot reservoir temperature is 64° C.
The pressure at 64 ° C is thus 1849.36 kPa by interpolation.
And, the lowest reservoir temperature must be calculated.



the lowest reservoir temperature = 258.703 kpa
So, the pressure ratio should be = 7.15
Answer:
And Im still going with B..
Answer:
the reason paper airplanes fly is because of lift the foil has no lift
Explanation:
Answer:
BOD concentration at the outflow = 17.83 mg/L
Explanation:
given data
flow rate of Q = 4,000 m³/day
BOD1 concentration of Cin = 25 mg/L
volume of the pond = 20,000 m³
first-order rate constant equal = 0.25/day
to find out
What is the BOD concentration at the outflow of the pond
solution
first we find the detention time that is
detention time t = 
detention time t = 
detention time = 5 days
so
BOD concentration at the outflow of pond is express as
BOD concentration at the outflow = 
here k is first-order rate constant and t is detention time and Cin is BOD1 concentration
so
BOD concentration at the outflow = 
BOD concentration at the outflow = 17.83 mg/L