Answer:
C)185,500 KJ
Explanation:
Given that
Latent heat fusion = 333.23 KJ/kg
Latent heat vaporisation = 333.23 KJ/kg
Mass of ice = 100 kg
Mass of water = 40 kg
Mass of vapor=60 kg
Ice at 0°C ,first it will take latent heat of vaporisation and remain at constant temperature 0°C and it will convert in to water.After this water which at 0°C will take sensible heat and gets heat up to 100°C.After that at 100°C vapor will take heat as heat of vaporisation .
Sensible heat for water Q
For water
Q=4.178 x 40 x 100 KJ
Q=16,712 KJ
So total heat
Total heat =100 x 333.23+16,712 + 60 x 2257 KJ
Total heat =185,455 KJ
Approx Total heat = 185,500 KJ
So the answer C is correct.
Answer:
b) Determine the heat transfer into the cycle and the net work for the cycle, in kJ.
Explanation:
Answer:
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Answer:
The flow of a real fluid has <u>more</u> complexity as compared to an ideal fluid owing to the phenomena caused by existence of <u>viscosity</u>
Explanation:
For a ideal fluid we know that there is no viscosity of the fluid hence the boundary condition need's not to be satisfied and the flow occur's without any head loss due to viscous nature of the fluid. The friction of the pipe has no effect on the flow of an ideal fluid. But for a real fluid the viscosity of the fluid has a non zero value, the viscosity causes boundary layer effects, causes head loss and also frictional losses due to pipe friction hugely make the analysis of the flow complex. The losses in the energy of the flow becomes complex to calculate as frictional losses depend on the roughness of the pipe and Reynolds number of the flow thus increasing the complexity of the analysis of flow.
Answer: 0.2m sqr
Explanation:
A well behaved aircraft basically have a value of volume in horizontal and vertical area.
Volume in horizontal area (Vh) = 0.6
Volume in vertical area (Vv) = 0.05
Having known this, consider the relationship to find the vertical and horizontal tail sizes.
Vertical tail area (Sv)
Horizontal tail area (Sh)
Vh= (Sh × I) / S
Where,
I = moment
S= wing area
Sh= Horizontal tail area
Vh= Volume in horizontal area
0.6= Sh × 10/40
24= 10Sh
Sh= 24/10
Sh= 2.4 msqr
Horizontal tail area= 2.4m sqr
From the information above, we can calculate the vertical tail area.
Vertical tail area is calculated thus below:
Vv= (Sv× I) / S
Where
Vv= Volume in vertical area
Sv= Vertical tail area
I= Moment
S= Wing area
Therefore
Sv= (Vv × S) /I
Sv= (0.05×40)/10
Sv= 0.2msqr
In conclusion, the vertical tail size is 0.2msqr
