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Lera25 [3.4K]
2 years ago
13

How do you ask someone out?

Physics
2 answers:
vazorg [7]2 years ago
4 0

talk, make conversation. text isnt always the answer, but sadly now it is. text them or better yet, call them. you can talk and then do not just blurt it out. say it calmly. they say yes, congrats, but if they say no, do not have a mental breakdown. it might ruin a friendship.

aleksandr82 [10.1K]2 years ago
3 0

Answer:

Send them a Snap and start a conversation. Say if I liked you would you feel the same way. Good Luck.

Explanation:

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The moons of Mars, Phobos (Fear) and Deimos (Terror), are very close to the planet compared to
katrin2010 [14]

Answer:D- 0.2528

Explanation:

T=(Rp/Rd)^3/2

T=(9378/23459)^3/2

T=0.2528

The answer is D

3 0
3 years ago
Plz help me
Reil [10]

Answer:

Yes

Explanation:

When an object has more mass it takes more gravity to keep it down therefore producing friction which in return reduces the amount of kinetic energy created. A change in an object's speed has an greater effect on its kinetic energy. than a change in its mass has, because kinetic energy is proportional to.

3 0
3 years ago
Joe and Max shake hands and say goodbye. Joe walks east 0.40 km to a coffee shop, and Max flags a cab and rides north 3.65 km to
katen-ka-za [31]

Answer:

3.67 km

Explanation:

Joe distance towards coffee shop is,

OB=0.40 km

And the Max distance towards bookstore is,

OA=3.65 km

Now the distance between the Joy and Max will be,

By applying pythagorus theorem,

AB=\sqrt{OB^{2}+OA^{2}}

Substitute 0.40 km for OB and 3.65 km for OA in the above equation.

AB=\sqrt{0.40^{2}+3.65^{2}}\\AB=\sqrt{13.4825} \\AB=3.67 km

Therefore the distance between there destination is 3.67 km.

6 0
3 years ago
What are two situational examples of unbalanced forces?
polet [3.4K]

An example of a balanced force is two cards leaning against each other and not falling over, or two football players blocking each other but neither overpowering the other. An example of an unbalanced force is two cards leaning on each other then falling over, or two football players blocking each other, then one tackles the other.

4 0
3 years ago
The top of the pool table is 0.810 m from the floor. the placement of the tape is such that 0 m is aligned with the edge of the
8090 [49]
Compute first for the vertical motion, the formula is:

y = gt²/2 

0.810 m = (9.81 m/s²)(t)²/2 

t = 0.4064 s 


whereas the horizontal motion is computed by: 

x = (vx)t 

4.65 m = (vx)(0.4064 s) 

4.65 m/ 0.4064s = (vx)

(vx) = 11.44 m / s
So look for the final vertical speed. 

(vy) = gt 

(vy) = (9.81 m/s²)(0.4064 s) 

(vy) = 3.99 m/s 


speed with which it hit the ground: 

v = sqrt[(vx)² + (vy)²] 

v = sqrt[(11.44 m/s)² + (3.99 m/s)²] 

v = 12.12 m / s
6 0
3 years ago
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