Question

Consider an electrical circuit which has two 50.0- resistors connected in parallel with each other. This pair of resistors is wired in series with a third identical resistor. The current supplied to the circuit comes from a 24.0-V battery.
a. Calculate the equivalent resistance for the circuit.

b. Calculate the current flowing through each resistor.

c. Calculate the total current flowing through the circuit.

Answer 1

The equivalent resistance for the circuit is 25 ohms.

The current flowing through each resistor is 0.48 A.

The total current flowing through the circuit is 0.96 A.

What is equivalent resistance for the circuit?

The equivalent resistance of the parallel circuit is calculated as follows;

1/Rt = 1/R1 + 1/R2

where;

• Rt is the equivalent resistance
• R1 is the first resistance
• R2 is the second resistance

1/Rt = 1/50 + 1/50

1/Rt = 0.04

Rt = 1/0.04

Rt = 25 ohms

The current through each resistor is calculated as follows;

Current in first resistor = V/R1

Current in first resistor =  24 / 50 = 0.48 A

Current in second resistor = V/R2

Current in second resistor =  24 / 50 = 0.48 A

The total current in the parallel circuit is calculated as follows;

I = V/Rt

I = 24/25

I = 0.96 A

OR

add the first and second current together = 0.48 A + 0.48 A = 0.96 A.

Learn more about current in parallel circuit here: brainly.com/question/24155667

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