Answer:
The speed of man before he hits the ground is <u>23.35 m/s</u>
Explanation:
We know that:
Weight of Man - Force of Friction = Unbalanced Force
but, from Newton's 2nd Law of Motion:
unbalanced force = ma
Therefore,
W - F = ma
a = (W - F)/m
a = (mg - F)/m
where,
m = 81 kg
g = 9.8 m/s²
F = 103 N
a = [(81 kg)(9.8 m/s²) - 103 N]/81 kg
a = 8.52 m/s²
using 3rd equation of motion:
Vf² - Vi² = 2ah
here,
Vi = initial velocity = 0 m/s
Vf = Final Velocity before he hits ground = ?
Vf² - 0² = 2(8.52 m/s²)(32 m)
Vf = √545.28 m²/s²
<u>Vf = 23.35 m/s</u>
The initial velocity of the train is 12.56 m/s.
<h3>
Initial velocity</h3>
The initial velocity of the train can be determined by using the first kinematic equation as shown below;
v = u + at
u = v - at
where;
- v is the final velocity = 110 km/h = 30.56 m/s
- u is the initial velocity
u = 30.56 - (36 x 0.5)
u = 12.56 m/s
Thus, the initial velocity of the train is 12.56 m/s.
Learn more about initial velocity here: brainly.com/question/19365526
Because a variable is an important stratagy of science
Answer:
86.6Nm(j)
Explanation:
we know,
w=Fd
w=17.32*5
w=86.6Nm.
as we know the distance but we doesnot know the exact force .becauseit acts at an angle.This mean the orginal force of 20N is essentially split up in 2 direction in along axis of displacement ,and perpendincular direction that occur at 30degree angle.
the resultant displacement of object is along a line inclined by 30 degrees of that orginal plane ,then the force acting in the direction of that displacement equal to 20*cos30.I.e,17.32 .
Answer:
The angular magnification is
Explanation:
From the question we are told
The focal length is
The near point is
The angular magnification is mathematically represented as
Substituting values