Answer:
Explanation:
The reaction of gaseous sulfur dioxide and oxygen to form SO3 (g) is:
2SO₂(g) + O₂(g) ⇄ 2SO₃(g)
Kp is defined as the ratio of pressure of products and pressure of reactants:
I hope it helps!
<h3>
Answer:</h3>
51.93 L
<h3>
Explanation:</h3>
From the question we are given the following components of an ideal gas;
Number of moles = 21.5 mol
Pressure, P = 9.65 atm
Temperature, T = 10.90°C, but K= °C + 273.15
=284.05 k
We are required to calculate the volume of the ideal gas.
We are going to use the ideal gas equation which is given by;
PV = nRT, where P, V, T and n are the pressure, volume, temperature and moles of the ideal gas respectively. R is the ideal gas constant, 0.082057 L.atm/mol.K
To get the volume, we rearrange the formula to get;
V = nRT ÷ P
= (21.5 × 0.082057 × 284.05 K) ÷ 9.65 atm
= 51.93 L
Thus, the volume of the ideal gas is 51.93 L
Do you need us to balance it?
Answer:
We can say, there are 4 mol of oxygen with (4 . NA) = 2.40ₓ10²⁴ atoms
Or just, 4 atoms oxygen.
Explanation:
CH₄ + 2O₂ → CO₂ + 2H₂O
1 mol of methane reacts with 2 mol of oxygen to produce 1 mol of carbon dioxide and 2 mol of water.
We count in 1 mol of CO₂, we have 2 mol of oxygen
In 2 mol of water, we have 2 mol of oxygen.
We can say, there are 4 mol of oxygen with (4 . NA) = 2.40ₓ10²⁴ atoms
Or just, 4 atoms oxygen.
Answer:
Yes.
Explanation:
Yes, I did see a wave that formed and rolled down the line because of tapping the stick on one end of the tape. The wave that had been created goes from one side of the tape to the other end of the tape. This movement occur in the tape due to the disturbance at one end of the tape so we can say that wave formed in the tape and rolled down the line.
