A small rubber ball is thrown at a heavier, larger basketball that is still. The small ball bounces off the basketball. Assume t
2 answers:
A. How does the force on the small ball compare to the force on the basketball?
Answer:
Force will be same in magnitude but opposite in sign
Explanation:
As per Newton's III law every action has equal and opposite reaction force.
So here when small ball apply force on large ball then the two forces will be equal in magnitude but opposite in direction
B. Compare the total momentum of the two balls before and after the collision?
Answer:
Total momentum of two balls will remains same before and after collision
Explanation:
As we know that there is no external force on the system of two bodies so the sum of momentum of two balls before and after collision must be same.
So we can say initial momentum of small ball = final momentum of small + big ball together.
C. The mass of the basketball is 600 grams and its velocity before the small ball hits is 0 m/s. The mass of the small ball is 100 grams and its velocity is +5 m/s before the collision and -4 m/s afterward. What is the velocity of the basketball after the collision?
Answer:
Explanation:
By momentum conservation equation we have
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By balancing forces, the force of the weight must be counteracted by the buoyancy force, therefore
Here,
m = mass
g =Gravitational energy
The buoyancy force corresponds to that exerted by water, while the mass given there is that of the object, therefore
Remember the expression for which you can determine the relationship between mass, volume and density, in which
In this case the density would be that of the object, replacing
Since the displaced volume of water is 0.429 we will have to
The density of water under normal conditions is , so
The density of the object is