A. How does the force on the small ball compare to the force on the basketball?
Answer:
Force will be same in magnitude but opposite in sign
Explanation:
As per Newton's III law every action has equal and opposite reaction force.
So here when small ball apply force on large ball then the two forces will be equal in magnitude but opposite in direction
B. Compare the total momentum of the two balls before and after the collision?
Answer:
Total momentum of two balls will remains same before and after collision
Explanation:
As we know that there is no external force on the system of two bodies so the sum of momentum of two balls before and after collision must be same.
So we can say initial momentum of small ball = final momentum of small + big ball together.
C. The mass of the basketball is 600 grams and its velocity before the small ball hits is 0 m/s. The mass of the small ball is 100 grams and its velocity is +5 m/s before the collision and -4 m/s afterward. What is the velocity of the basketball after the collision?
Answer:
Explanation:
By momentum conservation equation we have
Explanation:
The given data is as follows.
Spring constant (k) = 78 N/m,
Mass of block (m) = 0.50 kg
According to the formula of energy conservation,
mgh sin
h =
=
= 0.64 m
Thus, we can conclude that the distance traveled by the block is 0.64 m.
Complete Question
A person throws a pumpkin at a horizontal speed of 4.0 m/s off a cliff. The pumpkin travels 9.5m horizontally before it hits the ground. We can ignore air resistance.What is the pumpkin's vertical displacement during the throw? What is the pumpkin's vertical velocity when it hits the ground?
Answer:
The pumpkin's vertical displacement is
The pumpkin's vertical velocity when it hits the ground is
Explanation:
From the question we are told that
The horizontal speed is
The horizontal distance traveled is
The horizontal distance traveled is mathematically represented as
Where t is the time taken
substituting values
=>
Now the vertical displacement is mathematically represented as
now the vertical velocity before the throw is zero
So
Now the final vertical velocity is mathematically represented as
substituting values
Explanation:
i hope this helps, its not the same person but its the same equation.
