A. How does the force on the small ball compare to the force on the basketball?
Answer:
Force will be same in magnitude but opposite in sign
Explanation:
As per Newton's III law every action has equal and opposite reaction force.
So here when small ball apply force on large ball then the two forces will be equal in magnitude but opposite in direction
B. Compare the total momentum of the two balls before and after the collision?
Answer:
Total momentum of two balls will remains same before and after collision
Explanation:
As we know that there is no external force on the system of two bodies so the sum of momentum of two balls before and after collision must be same.
So we can say initial momentum of small ball = final momentum of small + big ball together.
C. The mass of the basketball is 600 grams and its velocity before the small ball hits is 0 m/s. The mass of the small ball is 100 grams and its velocity is +5 m/s before the collision and -4 m/s afterward. What is the velocity of the basketball after the collision?
Answer:
Explanation:
By momentum conservation equation we have
Answer:3.6
Explanation:
Given
Architect decide to double the width
length increases by 50 percent
height increases by 20 percent
Let L,B,H be length,height and width of rectangular room
L'=1.5L
B'=2B
H'=1.2H
therefore new volume V'=L'\times B'\times H'
V'=3.6LBH
new volume is 3.6 times the original
Answer:
time of collision is
t = 0.395 s
so they will collide at height of 5.63 m from ground
Explanation:
initial speed of the ball when it is dropped down is
similarly initial speed of the object which is projected by spring is given as
now relative velocity of object with respect to ball
now since we know that both are moving under gravity so their relative acceleration is ZERO and the relative distance between them is 6.4 m
Now the height attained by the object in the same time is given as
so they will collide at height of 5.63 m from ground