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Eddi Din [679]
1 year ago
7

you are about to work some magic with matter. you have a rectangular cube of matter in its solid state. it measures 3 in x 4 in

x 5 in. you have available a rectangular container measuring 5 in x 6 in x 3 in. you also have a cylindrical container witb base radius of 2.5 in and height 8 in. illustrate how that matter "fits" in each container when it is in its solid, liquid, and gaseous state.
Physics
1 answer:
Elenna [48]1 year ago
6 0

In solid and liquid the matter can occupy the 90 in³ and 157.1 in³ volume.

The matter in gaseous state can be expanded to occupy the volumes of the container.

<h3>Volume of each of the container</h3>

The volume of each of the container is calculated as follows;

<h3>Volume of the rectangular container</h3>

V = 5 in x 6 in x 3 in

V = 90 in³

<h3>Volume of the cylindrical container</h3>

V = πr²h

V = (π)(2.5 in)²(8 in)

V = 157.1 in³

<h3>Volume of the matter</h3>

Vm = 3 in x 4 in x 5 in

Vm = 60 in³

<h3>Matter in solid and liquid state</h3>

Matter has fixed volume in solid and liquid state.

In solid and liquid the matter can occupy the 90 in³ and 157.1 in³ volume.

<h3>Matter in gaseous state</h3>

Matter has no definite volume in gaseous state.

The matter in gaseous state can be expanded to occupy the volumes of the container.

Learn more about states of matter here:

#SPJ1

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Answer:

7.1934 x 10^12 V/m.s

Explanation:

In order to do this exercise, you need to use the correct formula. Besides that, we need to identify our data.

First we have the radius of the plates which are circular, and it's 0.1 m. The current of the loop (I) is 2.0 A, and the radius of the loop is 0.2 m.

Now with this data, we use the next formula:

I = dE/dt Eo A

Where:

dE/dt = rate of electric field

Eo = constant of permittivity of free space

A = Area of circle

Solving for dE/dT:

dE/dt = I / Eo*A

Now, the area of the circle is A = πr²

A = 3.1416 * (0.1)² = 0.031416 m²

Now solving the electric field:

dE/dt = 2 / (8.85x10^-12 * 0.031416)

dE/dt = 7.1934 x 10^12 V/m.s

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3 years ago
A piece of Nichrome wire has a radius of 6.5 104 m. It is used in a laboratory to make a heater that uses 4.00 102 W of power wh
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Answer:

L=4.8*10^{17}m

Explanation:

Given data

Power P=4.00×10²W

Radius r=6.5×10⁴m

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To find

Length of wire L

Solution

We know that resistance of wire can be obtained from

P=\frac{V_{2}}{R}\\ R=\frac{V_{2}}{P}

We also know that R=pL/A solving the length noting that A=πr²

and using p=100×10⁻⁸Ω.m we find that

So

L=\frac{RA}{p}\\ L=\frac{\frac{(V^{2})}{P}(\pi r^{2}) }{p} \\L=\frac{V^{2}(\pi r^{2})}{pP}\\ L=\frac{(120V)^{2}\pi (6.5*10^{4} m)^{2}  }{100*10^{-8}(4.00*10^{2} W) }\\ L=4.8*10^{17}m

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The same strength force was exerted in the same direction on both Object A and Object B. Why did Object A go faster than Object
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Answer:

m_B > m_A

the mass of body B must be greater than the mass of body A

Explanation:

Newton's second law establishes a linear relationship between the force, the mass of the body and its acceleration

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        a = F / m

Let's analyze this expression tells us that the force is of equal magnitude for the two bodies, but body A goes faster than body B, this implies that it has more relationships

         a_A > a_B

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3 years ago
Which describes a force acting on an object?
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Answer:

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Answer with Explanation:

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Distance moved by object,d=0.6 m

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Height,h=1.5 m

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b.

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W_{friction}=3\times 9.8\times 1.5-37.8=6.3 J

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