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Eddi Din [679]
1 year ago
7

you are about to work some magic with matter. you have a rectangular cube of matter in its solid state. it measures 3 in x 4 in

x 5 in. you have available a rectangular container measuring 5 in x 6 in x 3 in. you also have a cylindrical container witb base radius of 2.5 in and height 8 in. illustrate how that matter "fits" in each container when it is in its solid, liquid, and gaseous state.
Physics
1 answer:
Elenna [48]1 year ago
6 0

In solid and liquid the matter can occupy the 90 in³ and 157.1 in³ volume.

The matter in gaseous state can be expanded to occupy the volumes of the container.

<h3>Volume of each of the container</h3>

The volume of each of the container is calculated as follows;

<h3>Volume of the rectangular container</h3>

V = 5 in x 6 in x 3 in

V = 90 in³

<h3>Volume of the cylindrical container</h3>

V = πr²h

V = (π)(2.5 in)²(8 in)

V = 157.1 in³

<h3>Volume of the matter</h3>

Vm = 3 in x 4 in x 5 in

Vm = 60 in³

<h3>Matter in solid and liquid state</h3>

Matter has fixed volume in solid and liquid state.

In solid and liquid the matter can occupy the 90 in³ and 157.1 in³ volume.

<h3>Matter in gaseous state</h3>

Matter has no definite volume in gaseous state.

The matter in gaseous state can be expanded to occupy the volumes of the container.

Learn more about states of matter here:

#SPJ1

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Leno4ka [110]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

As we know, Displacement =

\qquad \sf  \dashrightarrow \: velocity  \times time

\qquad \sf  \dashrightarrow \: 6.8 \times 250

\qquad \sf  \dashrightarrow \: 1700 \: m

<h3>OR </h3>

\qquad \sf  \dashrightarrow \: 1.7 \: km

The car travelled 1700 meters ( 1.7 km )

8 0
2 years ago
A lab cart with a mass of 15 kg is moving with constant
bagirrra123 [75]

Answer:c

Explanation: i guessed but got it right bc im a bad bleep lol

8 0
3 years ago
a current of 5 ampere is passed for 2 hours in an electric iron having a resistance of 100 ohms calculate the heat produced
Alina [70]

Answer:

\boxed{\sf Heat \ produced \ (H) = 5 \ kWh}

Given:

Resistance (R) = 100 Ω

Current (I) = 5 A

Time (t) = 2 hours

To Find:

Heat developed (H) in the electric iron

Explanation:

Formula:

\boxed{ \bold{ \sf H = I^2Rt}}

Substituting values of I, R & t in the equation:

\sf \implies H =  {5}^{2}  \times 100 \times 2 \\  \\ \sf \implies H = 25 \times 100 \times 2 \\  \\  \sf \implies H = 5000  \\  \\ \sf \implies H = 5 \: kWh

\therefore

Heat developed (H) in the electric iron = 15 kWh

3 0
3 years ago
Problem 8: Consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric fi
yanalaym [24]

Answer:

10581.59 V

Explanation:

We are given that

Magnetic field=B=0.65 T

Speed of electron=v=6.1\times 10^7m/s

Charge on electron, q=e=1.6\times 10^{-19} C

Mass of electron,m_e=9.1\times 10^{-31} kg

We have to find the potential difference in volts required in the first part of the experiment to accelerate electrons.

V=\frac{v^2m_e}{2e}

Where V=Potential difference

m_e=Mass of electron

v=Velocity of electron

Using the formula

V=\frac{(6.1\times 10^7)^2\times 9.1\times 10^{-31}}{2\times 1.6\times 10^{-19}}

V=10581.59 V

Hence, the potential difference=10581.59 V

8 0
3 years ago
What is the exact distance from the Earth to the Sun?
notka56 [123]
94.5 million miles.

I hope this helps, please Brainliest me, and have a great night! :D
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