RADIATION
There are three types of heat transfer or heat propagation; conduction, convection and radiation. Heat transfer is the process by which heat projects externally however, depending on the temperature and pressure. Also called the movement of heat from a low temperatured state which increases as heat progresses.
Conduction is the heat transfer by contact, immediate contact.
Convection is the transfer of heat through air and water.
<span>Radiation is the transfer of heat regardless of the presence of atoms or particles.<span>
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Answer:
The function is x = e^(-t/2) * (0.792*sin12t + 5cos12t)
Explanation:
we have to:
m = mass = 4 kg
k = spring constant = 577 N/m
c = damping constant = 4 N*s/m
The differential equation of motion is equal to:
m(d^2x/dt^2) + c(dx/dt) + k*x = 0
Replacing values:
4(d^2x/dt^2) + 4(dx/dt) + 577*x = 0
Thus, we have:
4*x^2 + 4*x + 577 = 0
we will use the quadratic equation to solve the expression:
x = (-4 ± (4^2 - (4*4*577))^1/2)/(2*4) = (-4 ± (-9216))/8 = (1/2) ± 12i
The solution is equal to:
x = e^(1/2) * (c1*sin12t + c2*cos12t)
x´ = (-1/2)*e^(1/2) * (c1*sin12t + c2*cos12t) + e^(-t/2) * (12*c1*cos12t - 12*c2*sin12t)
We have the follow:
x(0) = 5
e^0(0*c1 + c2) = 5
c2 = 5
x´(0) = 7
(-1/2)*e^0 * (0*c1 + c2) + e^0 * (12*c1 - 0*c2) = 7
(-1/2)*(5) + 12*c1 = 7
Clearing c1:
c1 = 0.792
The function is equal to:
x = e^(-t/2) * (0.792*sin12t + 5cos12t)
Answer:
-142m
Explanation:
To find the initial position of the car, we can add the displacement.
-245 + 103 = -142
Best of Luck!
The "newton-meter" that is a unit of work or energy
is identical to the Joule.
<h2>
Answer: B. False</h2>
Explanation:
According to Bernoulli's principle:
<em>"In an ideal fluid (not viscous and without friction) that circulates through a closed conduit, the energy the fluid possesses remains constant along its path."
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From there, Bernoulli deduced that the fluid pressure decreases when the flow rate increases. <u>And this has nothing to do with depth.
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<u>
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To understand it better:
In a fluid that circulates through a closed conduit (a pipe for example), it contains energy in two ways:
-Kinetic energy due to its <u>weigh</u>t and <u>speed.
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-Potential energy in the form of <u>pressure.
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Now, if the system has constant flow and the total energy (kinetic + potential) is also constant, <u>the energy is transformed every time the transverse area of the tube is modified.
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It should be noted that by modifying this transverse area, the flow rate is also modified.
Therefore, <u>as the kinetic energy increases or decreases, this change is compensated by the decrease or increase in pressure</u> (potential energy), since the total energy of the system cannot be created or destroyed.